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soldi70 [24.7K]
4 years ago
11

The environment between the outer and inner nuclear membranes is most accurately referred to as the:

Physics
1 answer:
jenyasd209 [6]4 years ago
5 0
C.Perinuclear Space
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Two narrow slits are 0.12 mm apart. light of wavelength 550 nm illuminates the slits, causing an interference pattern on a scree
mamaluj [8]

Answer:

500 nm

Explanation:

d_l = Distance traveled by light from left slit

d_r = Distance traveled by light from right slit

\Delta x = Path difference = d_l-d_r

m = Order = 1

\lambda = Wavelength = 550 nm

Path difference is given by

\Delta x=m\lambda\\\Rightarrow d_l-d_r=1\times 550\\\Rightarrow d_l-d_r=500\ nm

The required distance is 500 nm

3 0
3 years ago
While riding in a moving car, you toss an egg directly upward. Does the egg tend to land behind you, in front of you, or back in
bazaltina [42]

Answer:

Explanation:

The movement of a body can be analyzed using New's first law. In an inertial frame (without acceleration) every body is kept at rest or moving at constant speed until there is an external force that changes this state

Let's analyze these cases in the framework of this first law

a) If the vehicle is going at constant speed the two bodies (the egg and the hands) do not change movement so he had returned to the hands

b) If the vehicle accelerates the passenger goes faster, but the egg that is not subject to anything does not change the movement, so it falls behind the passenger

c) If the vehicle slows down, the passenger reduces its speed and the distance traveled in time, but the egg that is not attached follows its movement and falls in front of the passenger.

4 0
3 years ago
Can anyone answer this question for me please..​
motikmotik

Answer:

You have to sub x in for the number you dont know and then solve for x.

Explanation:

10(5+x)=90

50+10x=90

10x=40

x=4

8 0
3 years ago
(a) A load of coal is dropped (straight down) from a bunker into a railroad hopper car of inertia 3.0 × 104 kg coasting at 0.50
Firlakuza [10]

Answer:

a) m=20000Kg

b) v=0.214m/s

Explanation:

We will separate the problem in 3 parts, part A when there were no coals on the car, part B when there is 1 coal on the car and part C when there are 2 coals on the car. Inertia is the mass in this case.

For each part, and since the coals are thrown vertically, the horizontal linear momentum p=mv must be conserved, that is, p=m_Av_A=m_Bv_B=m_Cv_C, were each velocity refers to the one of the car (with the eventual coals on it) for each part, and each mass the mass of the car (with the eventual coals on it) also for each part. We will write the mass of the hopper car as m_h, and the mass of the first and second coals as m_1 and m_2 respectively

We start with the transition between parts A and B, so we have:

m_Av_A=m_Bv_B

Which means

m_hv_A=(m_h+m_1)v_B

And since we want the mass of the first coal thrown (m_1) we do:

m_hv_A=m_hv_B+m_1v_B

m_hv_A-m_hv_B=m_1v_B

m_1=\frac{m_hv_A-m_hv_B}{v_B}=\frac{m_h(v_A-v_B)}{v_B}

Substituting values we obtain

m_1=\frac{(3\times10^4Kg)(0.5m/s-0.3m/s)}{0.3m/s}=20000Kg=2\times10^4Kg

For the transition between parts B and C, we can write:

m_Bv_B=m_Cv_C

Which means

(m_h+m_1)v_B=(m_h+m_1+m_2)v_C

Since we want the new final speed of the car (v_C) we do:

v_C=\frac{(m_h+m_1)v_B}{(m_h+m_1+m_2)}

Substituting values we obtain

v_C=\frac{(3\times10^4Kg+2\times10^4Kg)(0.3m/s)}{(3\times10^4Kg+2\times10^4Kg+2\times10^4Kg)}=0.214m/s

5 0
3 years ago
Questions 14 out of 20
KiRa [710]

Answer:

B

Explanation:

4 0
4 years ago
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