Your answer should be “1.”
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Answer: In the case of gravity, mediated by spin 2 particles, charge is mass, which is always positive. Thus, q1q2 is always greater than zero, and gravity is always attractive. For spin 0 force mediators, however, there is no restriction on the charges and you can very well have repulsive forces.
Explanation: C) both an attractive and repulsive force is the answer
Answer:
50m; 0m/s.
Explanation:
Given the following data;
Initial velocity = 20m/s
Acceleration, a = - 4m/s²
Time, t = 5secs
To find the displacement, we would use the second equation of motion;

Substituting into the equation, we have;



S = 50m
Next, to find the final velocity, we would use the third equation of motion;
Where;
- V represents the final velocity measured in meter per seconds.
- U represents the initial velocity measured in meter per seconds.
- a represents acceleration measured in meters per seconds square.
<em>Substituting into the equation, we have;</em>
V = 0m/s
<em>Therefore, the displacement of the bus is 50m and its final velocity is 0m/s.</em>
Answer:
v = 60 m/s
Explanation:
It is given that,
A wave is represented by the equation :
![y=0.2\sin [0.4\pi (x-60)t]](https://tex.z-dn.net/?f=y%3D0.2%5Csin%20%5B0.4%5Cpi%20%28x-60%29t%5D)
We need to find the velocity of the wave
The general equation of a wave is given by :
....(1)
Equation (1) can be written as :
...(2)
If we compare equation (1) and (2) we get :


The velocity of a wave is given by :

So, the velocity of the wave is 60 m/s.
Answer:
The primary reason of seeing the cracker burst and hearing the sound later is because the speed of sound and light. Speed of light is in the vicinity of 3*10^8m,/ sec while the speed of sound is at a distance of 332m/sec. It is similar to lightning that strikes before the sound.
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