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3 years ago

Do transistors amplfy a.c or d.c

Physics

2 answers:

Papessa [141]3 years ago

7 0

Answer:

Yes,by using direct coupling(transistors) amplifier we will amplify low frequency (DC) signals. A transistor is certainly capable of taking a small-current input signal and controlling a high-current output at the same voltage, thereby amplifying the power of the input signal whether it's AC or DC.

Can you give me brainliest?please?

Gnoma [55]3 years ago

5 0

Explanation:

thet amplify DC, because of the voltage ( small current input signal)

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A current-carrying wire passes through a region of space that has a uniform magnetic field of 0.92 T. If the wire has a length o

alex41 [277]

Answer:

Current, I = 2.45 T

Explanation:

It is given that,

Magnetic field, B = 0.92 T

Length of wire, l = 2.6 m

Mass, m = 0.6 kg

We need to find the minimum current needed to levitate the wire. It is given by balancing its weight to the magnetic force i.e.

$Ilb=mg$

$I=\dfrac{mg}{lB}$

$I=\dfrac{0.6\ kg\times 9.8\ m/s^2}{2.6\ m\times 0.92\ T}$

I = 2.45 A

So, the minimum current to levitate the wire is 2.45 T. Hence, this is the required solution.

7 0

4 years ago

Explain how thermal conductivity occurs in poor conductor materials

DIA [1.3K]

Answer:

• As heat is applied to one end of this material, atoms in the hotter region gain vibràtory energy at a maximum amplitude. They transfer it on to their neighboring atoms and heat is transfered along this material in form of vibràtory energy.

Explanation:

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3 0

3 years ago

Read 2 more answers

Look at the equation. What detail is missing? 3 m/s2= (33 m/s - X)/30 S <br>

Tems11 [23]

Answer:

The starting velocity.

Explanation:

We must understand that this equation comes from the following equation of kinematics.

$v_{f}=v_{o}+a*t$

where:

Vf = final velocity = 33 [m/s]

Vo = starting velocity [m/s]

a = acceleration = 3 [m/s²]

t = time = 30 [s]

So, these values can be assembly in the following way:

$v_{f}=v_{o}+a*t\\a*t=v_{f}-v_{o}\\3=\frac{33-v_{o}}{30}$

6 0

3 years ago

In a circuit, a current of 2.0 A is drawn from a battery. The current then divides and passes through two resistors in parallel.

gizmo_the_mogwai [7]

Answer:

2.4

Explanation:

6 0

3 years ago

The angular momentum of a flywheel having a rotational inertia of 0.142 kg·m2 about its central axis decreases from 7.20 to 0.14

luda_lava [24]

Answer:

3.3619 Nm

54.27472 rad

182.46618 J

86.88 W

Explanation:

$L_i$ = Initial angular momentum = 7.2 kgm²/s

$L_f$ = Final angular momentum = 0.14 kgm²/s

I = Moment of inertia = 0.142 kgm²

t = Time taken

Average torque is given by

$\tau_{av}=\frac{L_f-L_i}{\Delta t}\\\Rightarrow \tau_{av}=\frac{0.14-7.2}{2.1}\\\Rightarrow \tau_{av}=-3.3619\ Nm$

Magnitude of the average torque acting on the flywheel is 3.3619 Nm

Angular speed is given by

$\omega_i=\frac{L_i}{I}$

Angular acceleration is given by

$\alpha=\frac{\tau}{I}$

From the equation of rotational motion

$\theta=\omega_it+\frac{1}{2}\alpha t^2\\\Rightarrow \theta=\frac{L_i}{I}\times t+\frac{1}{2}\times \frac{\tau}{I}\times t^2\\\Rightarrow \theta=\frac{7.2}{0.142}\times 2.1+\frac{1}{2}\times \frac{-3.3619}{0.142}\times 2.1^2\\\Rightarrow \theta=54.27472\ rad$

The angle the flywheel turns is 54.27472 rad

Work done is given by

$W=\tau\theta\\\Rightarrow W=-3.3619\times 54.27472\\\Rightarrow W=-182.46618\ J$

Work done on the wheel is 182.46618 J

Power is given by

$P=\frac{W}{t}\\\Rightarrow P=\frac{-182.46618}{2.1}\\\Rightarrow P=-86.88\ W$

The magnitude of the average power done on the flywheel is 86.88 W

6 0

3 years ago

Do transistors amplfy a.c or d.c​

Do transistors amplfy a.c or d.c