3 years ago

How do I count atoms in science

Physics

1 answer:

VashaNatasha [74]3 years ago

6 0

Answer:

The "2" tells us that there are 2 hydrogen atoms in this compound.

Explanation:

You might be interested in

Define thermopile and peltiers??

NikAS [45]

Answer:

Thermopile is an electronic device that converts thermal energy into electrical energy.

A Peltier cooler, heater, or thermoelectric heat pump is a solid-state active heat pump which transfers heat from one side of the device to the other, with consumption of electrical energy, depending on the direction of the current.

3 0

3 years ago

WHY IS SATURN ONE OF THE COLDEST PLANETS IN OUR SOLAR SYSTEM

Usimov [2.4K]

What are the answer choices?

4 0

3 years ago

WEATHER: <br> What kind of weather occurs along this type of front?

Radda [10]

Cold front because the warm front or hit front is lower on the right and goes downwards and cold front is in the middle and goes to Minneapolis

4 0

3 years ago

Read 2 more answers

The hypotenuse of a right triangle is 29.0 centimeters. The length of one of its legs is 20.0 centimeters. What is the length of

Kisachek [45]

square root (29 squared - 20 squared)

Pythagoras' theorem

5 0

3 years ago

Read 2 more answers

If the magnitude of the magnetic field is 2.50 mT at a distance of 12.6 cm from a long straight current carrying wire, what is t

Aleksandr-060686 [28]

Answer:

The magnetic field at a distance of 19.8 cm from the wire is 1.591 mT

Explanation:

Given;

first magnetic field at first distance, B₁ = 2.50 mT

first distance, r₁ = 12.6 cm = 0.126 m

Second magnetic field at Second distance, B₂ = ?

Second distance, r₂ = ?

Magnetic field for a straight wire is given as;

$B = \frac{\mu I}{2 \pi r}$

Where:

μ is permeability

B is magnetic field

I is current flowing in the wire

r distance to the wire

$Let \ \frac{\mu I}{2\pi} \ be \ constant; = K\\\\B = \frac{K}{r} \\\\K = Br\\\\B_1r_1 = B_2r_2\\\\B_2 =\frac{B_1r_1}{r_2} \\\\B_2 = \frac{2.5*10^{-3} *0.126}{0.198} \\\\B_2 = 1.591 *10^{-3}\ T\\\\B_2 = 1.591 \ mT$

Therefore, the magnetic field at a distance of 19.8 cm from the wire is 1.591 mT

7 0

3 years ago