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I am Lyosha [343]
3 years ago
12

Which of the following is the best definition of radiation?

Chemistry
2 answers:
mafiozo [28]3 years ago
6 0

Answer: Option (D) is the correct answer.

Explanation:

When heat or energy is transferred through the space in the form of waves or through a material medium then it is know as radiation.

For example, when we take Sun bath then our body gets warm due to solar radiation.

For transfer of heat through radiation it is not necessary that the objects have to in contact with each other.

Thus, we can conclude that out of the given options, the transmission of heat without any contact.

Fofino [41]3 years ago
5 0

the Answer would be D

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How much energy in kJ is associated with a radio wave of wavelength 1.2 X 10^2 m?
eduard
It's very simple.

Energy = \frac{hc}{\lambda}

where, h= Planck's constant = 6.6 x 10^{-34} m^2 kg/s

c= speed of light = 3 x 10^{8} m/s
\lambda = wavelength


So, energy = \frac{6.6 \times 10^{-34} \times 3 \times 10^{8}}{120}

= 1.65 x 10^{-27} J
=1.65 x 10^{-30} KJ

6 0
4 years ago
Using the mmoles of (35)-2,2,-dibromo-3,4-dimethylpentane calculated earlier and the molecular weight of the product (962 g/mol)
Sedbober [7]

Answer:

The yield of the product in gram is \mathsf{{w_P}=0.26 \ gram}

Explanation:

Given that:

the molecular mass weight of the product = 96.2 g/mol

the molecular mass of the reagent (3S)-2,2,-dibromo-3,4-dimethylpentane is 257.997 g

given that the millimoles of the reagent = 2,7 millimoles = 2.7 \times 10^{-3} \ moles

We know that:

Number of moles = mass/molar mass

Then:

2.7 \times 10^{-3} = \dfrac{ mass}{257.997}

mass = 2.7 \times 10^{-3} \times 257.997

mass = 0.697

Theoretical yield = (number of moles of the product/ number of moles of reactant) × 100

i.e

Theoretical yield = \dfrac{n_P}{n_R}\times 100\%

where;

n_P = \dfrac{w_P}{m_P}    and n_R = \dfrac{w_R}{m_R}

Theoretical yield = \dfrac{(\dfrac{w_P}{m_P})}{(\dfrac{w_R}{m_R})} \times 100\%

Given that the theoretical yield = 100%

Then:

100\% =\dfrac{(\dfrac{w_P}{m_P})}{(\dfrac{w_R}{m_R})} \times 100\%

\dfrac{w_P}{m_P}=\dfrac{w_R}{m_R}

{w_P}=\dfrac{w_R \times m_P}{m_R}

where,

w_P = derived weight of the product

m_P =the molecular mass of the derived product

m_R = the molecular mass of the reagent

w_R = weight in a gram of the reagent

{w_P}=\dfrac{w_R \times m_P}{m_R}

{w_P}=\dfrac{0.697 \times 96.2}{257.997}

\mathsf{{w_P}=0.26 \ gram}

8 0
3 years ago
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zepelin [54]

Answer:

4. is the correct answer

Explanation:

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4 0
3 years ago
2. Under a pressure of 95kPa and a temperature of 25 C, a gas occupies 4.0 liters. What would the new
Alekssandra [29.7K]

Answer:

35

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multiply and subtract

3 0
3 years ago
Describe the differences between bonding in an ionic compound and bonding in a covalent molecule.
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a covalent bond and an ionic bond. An ionic bond if formed from the transfer of electrons from the outer shell of atoms. ... An example of this is NaCl, where the sodium atom becomes Na+ due to the loss of electrons, and the chlorine atom becomes the negatively charged chloride (Cl-).

8 0
3 years ago
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