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3 years ago

Given the diagram below determine the net force acting on the object

Physics

2 answers:

crimeas [40]3 years ago

7 0

A) 0

because all of the forces cancel out, so it is not moving with balanced forces.

zzz [600]3 years ago

6 0

Answer:

0 Newtons

Explanation:

As you can see in the image all of the forces that are contrary or opposite to one another have the same magnitude, that makes them cancel out, in order for an object to move the force applied most be greater than the force that is setting it at rest, usually the friction, unless one of this forces si greater than the other the object won´t move, so the net force acting on the object will be 0,

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makkiz [27]

Answer:

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Explanation:

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3 years ago

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Likurg_2 [28]

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4 years ago

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Answer:

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3 years ago

When the distance between two charges is halved, the electrical force between them?

Llana [10]

If the distance between two charges is halved, the electrical force between them increases by a factor 4.

In fact, the magnitude of the electric force between two charges is given by:
$F= k \frac{q_1 q_2}{r^2}$
where
k is the Coulomb's constant
q1 and q2 are the two charges
r is the separation between the two charges

We see that the magnitude of the force F is inversely proportional to the square of the distance r. Therefore, if the radius is halved:
$r'= \frac{r}{2}$
the magnitude of the force changes as follows:
$F'=k \frac{q_1 q_2}{r'^2}=k \frac{q_1 q_2}{( \frac{r}{2})^2 }=k \frac{q_1 q_2}{ \frac{r^2}{4} } =4k \frac{q_1 q_2}{r^2}=4 F$
so, the force increases by a factor 4.

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3 years ago