All categories

3 years ago

Given the diagram below determine the net force acting on the object

Physics

2 answers:

crimeas [40]3 years ago

7 0

A) 0

because all of the forces cancel out, so it is not moving with balanced forces.

zzz [600]3 years ago

6 0

Answer:

0 Newtons

Explanation:

As you can see in the image all of the forces that are contrary or opposite to one another have the same magnitude, that makes them cancel out, in order for an object to move the force applied most be greater than the force that is setting it at rest, usually the friction, unless one of this forces si greater than the other the object won´t move, so the net force acting on the object will be 0,

You might be interested in

Acceleration is rate of change of <br>A-Position<br>B-Time<br>C-Velocity<br>D-Speed

Drupady [299]

<h3>Answer:</h3>

[C] Velocity.

<h3>Explanation:</h3>

<u>As we know that</u>,

a = v - u/t

<u>where, a = acceleration, v = final velocity, u = initial velocity and t = time taken to travel</u>.

8 0

2 years ago

Read 2 more answers

A boxed 12.0 computer monitor is dragged by friction 7.50 up along the moving surface of a conveyor belt inclined at an angle of

sasho [114]

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.

Below is the solution:

W done by Normal = 0. (make the incline flat, Normal force goes directly up: no work done)
<span>W done by gravity = w*displacement = (11kg*9.8) * 7.5sin(35) = -463J </span>
<span>W done by friction is the opposite of the work done by weight because the object is not moving. Therefore W done by friction = 463J</span>

8 0

3 years ago

The force F required to compress a spring a distance x is given by F 2 F0 5 kx where k is the spring constant and F0 is the prel

IrinaVladis [17]

Answer:

a)W=8.333lbf.ft

b)W=0.0107 Btu.

Explanation:

<u>Complete question</u>

The force F required to compress a spring a distance x is given by F– F0 = kx where k is the spring constant and F0 is the preload. Determine the work required to compress a spring whose spring constant is k= 200 lbf/in a distance of one inch starting from its free length where F0 = 0 lbf. Express your answer in both lbf-ft and Btu.

Solution

Preload = F₀=0 lbf

Spring constant k= 200 lbf/in

Initial length of spring x₁=0

Final length of spring x₂= 1 in

At any point, the force during deflection of a spring is given by;

F= F₀× kx where F₀ initial force, k is spring constant and x is the deflection from original point of the spring.

$W=\int\limits^2_1 {} \, Fds \\\\\\W=\int\limits^2_1( {F_0+kx} \,) dx \\\\\\W=\int\limits^a_b {kx} \, dx ; F_0=0\\\\\\W=k\int\limits^2_1 {x} \, dx \\\\\\W=k*\frac{1}{2} (x_2^{2}-x_1^{2} )\\\\\\W=200*\frac{1}{2} (1^2-0)\\\\\\W=100.lbf.in\\\\$

Change to lbf.ft by dividing the value by 12 because 1ft=12 in

100/12 = 8.333 lbf.ft

work required to compress the spring, W=8.333lbf.ft

The work required to compress the spring in Btu will be;

1 Btu= 778 lbf.ft

?= 8.333 lbf.ft----------------cross multiply

(8.333*1)/ 778 =0.0107 Btu.

6 0

2 years ago

A spring scale exerts a net force of 8.5 N on an object. What is the object's mass if it has an acceleration of

Amiraneli [1.4K]

Answer:

mass of the object is 2.18 kg

Explanation:

Given

Force (F) = 8.5 N = 8.5 kg.m/ $s^{2}$

acceleration (a) = 3.9 m/ $s^{2}$

Mass (m) = ?

We know that the newton's second law of motion gives the relation between mass of ab object. force acted upon and the amount the object is accelerated. It is expressed in the form of an equation:

F = ma

mass, m = F/a

= $\frac{8.5 kgms^{-2} }{3.9 ms^{-2} }$

= 2.18 kg

4 0

3 years ago

Jill is getting ready to push little Frank in his swing. She pulls Frank back as high as she can and then releases the swing. Wh

makkiz [27]

The transfer of energy is potential energy to kinetic energy. The swing has potential energy when she pulls it back and once she lets go, allowing the swing to move, it then has kinetic energy.

5 0

2 years ago