Answer:
A planet's mass has no effect on its orbit around the Sun.
Explanation:
The kepler's third law tells us:
where 
is the orbit period and 
is the semi-major axis.
As we can see from the equation, the period depends only on the measure of the semi-major axis of the orbit, that is, how far a planet is from the sun.
The equation tells us that the closer a planet is to the sun, the faster it will go around it.
The mass does not appear in the equation to calculate the period.
This is why it is concluded from the third law of Kepler that<u> the period, or the orbit of a planet around the sun, does not depend on its mass.</u>
the answer i: A planet's mass has no effect on its orbit around the Sun.
Answer:42.4m/s^2
Explanation:
Velocity(v)=6m/s
Radius(r)=0.85 meter
Centripetal acceleration=(v x v) ➗ r
Centripetal acceleration=(6 x 6) ➗ 0.85
Centripetal acceleration=36 ➗ 0.85
Centripetal acceleration=42.4
D. Nucleus because it is not a part of the group.
Explanation:
use equation power=watts/time
to find time rearrange to make time = power/wats
so you have your equation substitute the numbers
so 9560J/860W is 11 minutes
Answer:
Solution:
we have given the equation of motion is x(t)=8sint [where t in seconds and x in centimeter]
Position, velocity and acceleration are all based on the equation of motion.
The equation represents the position. The first derivative gives the velocity and the 2nd derivative gives the acceleration.
x(t)=8sint
x'(t)=8cost
x"(t)=-8sint
now at time t=2pi/3,
position, x(t)=8sin(2pi/3)=4*squart(3)cm.
velocity, x'(t)=8cos(2pi/3)==4cm/s
acceleration, x"(t)==8sin(2pi/3)=-4cm/s^2
so at present the direction is in y-axis.
