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3 years ago

Uranus has more than 14 times as much mass as earth, yet the gravitational force is less. how can that be?

Physics

2 answers:

Black_prince [1.1K]3 years ago

4 0

Answer:

By the force of universal attraction

Explanation:

The gravitational attraction of a large body (planet) on an object on its surface can be calculated with the same equation of universal gravitation

F = G m1 m2 / r²

Where G is the Universal gravitation costing 6.67 10⁻¹¹ N m²/Kg², m1 the mass of the planet, r the distance that we can take equal to the average radius of the planet and m2 the mass of the object that we can leave out, what remains of the equation is called acceleration of the planet's gravity, let's write the equation explicitly

g = G m1 / r²

We look for the data of the two planets, for the earth, they are 5.98 10²⁴ kg and 6.37 10⁶ m for their mass and radius, respectively; for Uranus we have 8.68 10²⁵ Kg and 2.54 10⁷ m; Let's calculate the values of the acceleration of gravity for each

Earth

g = 6.67 10 -11 5.98 10 24 / (6.37 10 6) 2

g = 9.87 m / s

Uranus

g2 = 6.67 10 -11 8.68 10 25 / (2.54 10 7) 2

g2 = 8.97 m / s

We can see that the gravity of Uranus is less than the gravity of the earth.

This could be intuited since the force of gravity depends on the inverse of the square of the distance and only proportionally with the mass.

Anarel [89]3 years ago

3 0

It has more mass, yes. But it has less of a gravitational pull because it is farther away from the sun than the Earth is

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Calculate the net force on the right charge due to the other two. Enter a positive value if the force is directed to the right a

lbvjy [14]

Answer:

Answer:

A. - 0.017N. It acts to the left.

B. - 0.043N. It acts to the left.

C. 0.060N. It acts to the right.

Explanation:

A. For the +65μC charge, we consider it to be the origin. Hence, the two other charges are on the +x axis.

The net coulombs force on the charge is

F = [KQ(1)Q(2)]/(r^2) + [KQ(1)Q(3)]/(r^2)

Where K = Coloumbs constant =

Q(1) = charge on the leftmost side.

Q(2) = charge in the middle.

Q(3) = charge on the rightmost side.

F = [(8.988 × 10^9)×(65×10^-6)×(48×10^-6)]/(40^2) + [(8.988 × 10^9)×(-95×10^-6)×(65×10^-6)]/(40^2)

F = 0.01753 - 0.03469

F = -0.017N

It has a negative sign, hence, it acts to the left.

B. For the +48μC charge, we consider it to be the origin. Hence, the leftmost charge is on the - x axis and the rightmost charge is on the +x axis.

The net coulombs force on the charge is

F = [-KQ(1)Q(3)]/(r^2) + [KQ(2)Q(3)]/(r^2)

F = [-(8.988×10^9)×(65×10^-6)×(48×10^-6)]/(40^2) + [(8.988 × 10^9)×(48×10^-6)×(-95×10^-6)]/(40^2)

F = -0.017 - 0.02562

F = - 0.043N

It has a negative sign, hence, it acts to the left.

C. For the -95μC charge, we consider it to be the origin. Hence, the two other charges are on the - x axis.

The net coulombs force on the charge is

F = [-KQ(1)Q(3)]/(r^2) - [KQ(2)Q(3)]/(r^2)

F = [-(8.988×10^9)×(65×10^-6)×(-95×10^-6)]/(40^2) - [(8.988 × 10^9)×(48×10^-6)×(-95×10^-6)]/(40^2)

F = +0.03469 + 0.02562

F = +0.060N

It has a positive sign, hence, it acts to the right.

Read more on Brainly.com - brainly.com/question/14592748#readmore

Explanation:

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3 years ago

lightning is actually an enormous display of the concept of A.chemical heating B.solar energy C.magnetism D.grounding

allsm [11]

Answer:

D) Grounding

Explanation:

The potential difference between cloud and ground leads to ionization of the atmosphere and resulting conduction through the air often to ground (although it can be between clouds at different potentials. I would say grounding, like the spark when you touch a hot battery terminal to ground on a car.

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3 years ago

One gallon of paint (volume = 3.79 X 10-???? m3) covers an area of 25.0 m2. What i the thickne s of the fresh paint on the wall?

Drupady [299]

Answer:

Explanation:

Given

Volume of paint is $V=3.79\times 10^{-3}\ m^3$

Area of cover $A=25\ m^2$

Suppose paint to be a rectangular box with thickness t and volume V

therefore we can write as

$V=A\times t$

$t=\frac{V}{A}$

$t=\frac{3.79\times 10^{-3}}{25}$

$t=1.516\times 10^{-3}\ m$

$t=1.516\ mm$

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3 years ago

If an object accelerates from rest, with a constant of 8 m/s2, what will its velocity be after 35s?

AlladinOne [14]

Answer:

<em>Its speed will be 280 m/s</em>

Explanation:

<u>Constant Acceleration Motion</u>

It's a type of motion in which the speed of an object changes by an equal amount in every equal period of time.

If a is the constant acceleration, vo the initial speed, vf the final speed, and t the time, vf can be calculated as:

$v_f=v_o+at$

The object accelerates from rest (vo=0) at a constant acceleration of $a=8\ m/s^2$ . The final speed at t=35 seconds is:

$v_f=0+8*35$

$v_f=280\ m/s$

Its speed will be 280 m/s

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Explain the terms boiling and boiling point.

Volgvan

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