All categories

3 years ago

Please help me to fix this sentence to sentence with more delivery and fluency

Physics

2 answers:

Jlenok [28]3 years ago

6 0

Which amount of water is between how much water evaporates, and how much comes down during rainfall in the same day

s344n2d4d5 [400]3 years ago

5 0

Answer:

Is the amount of water evaporated in a day more significant than the amount of rain falling in a day?

Explanation:

Don't overcomplicate it

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Josh starts throwing his pitch; we assume that his arm moves in a perfect circular arc, and his arm is 0.7 m long. If he needs t

harina [27]

As we know that centripetal acceleration is given as

$a_c = \frac{v^2}{R}$

here we know that

linear speed = 35 m/s

here radius of path is same as length of arm

R = 0.7 m

now from above above formula we have

$a_c = \frac{35^2}{0.7}$

$a_c = 1750 m/s^2$

so acceleration is 1750 m/s/s

5 0

4 years ago

You have 750 g of water at 10°C in a large insulated beaker. How much boiling water at 100°C must you add to this beaker so that

lina2011 [118]

Answer:

Correct answer: m₂ = 1,950 g

Explanation:

When mixing the liquid, in this case water, at different temperatures, the warmer liquid will cool and the cooler will warm up until their temperatures equalize.

The amount of heat that the second fluid (water) releases is equal to the amount of heat that the first fluid (water) receives in this spontaneous process.

Q₁ = Q₂

Q₁ = m₁ c (t - t₁) and Q₂ = m₂ c (t₂ - t)

where are they: m₁ = 750 g, t₁ = 10°C, t₂ = 100°C, t = 75°C, m₂ = ?

m₁ c (t - t₁) = m₂ c (t₂ - t) \ : c

Since water is the liquid in question, it has the same specific heat capacity. Therefore, we will divide both sides of the equation by c and get:

m₁ (t - t₁) = m₂ (t₂ - t) => m₂ = m₁ (t - t₁) / (t₂ - t) =>

m₂ = 750 · (75 - 10) / (100 - 75) => m₂ = 750 · 65 / 25 = 1,950 g

m₂ = 1,950 g

God is with you!!!

4 0

4 years ago

Traveling 221 miles from Boston Back Bay Station to NYC Penn Station takes 3 hours

Nostrana [21]

Answer:

Approximately $116\; \text{miles}$ for the train from Boston to NYC Penn Station.

Approximately $105\; \text{miles}$ for the train from NYC Penn Station to Boston.

Explanation:

Convert minutes to hours:

$\begin{aligned}t(\text{BOS $\to$ NYC}) &= 3\; {\text{hour}} + 40\; \text{minute} \times \frac{1\; {\text{hour}}}{60\; \text{minute}} \\ &=\left(3 + \frac{2}{3}\right)\; \text{hour}\\ &= \frac{11}{3}\; \text{hour} \end{aligned}$ .

$\begin{aligned}t(\text{NYC $\to$ BOS}) &= 4\; {\text{hour}} + 5\; \text{minute} \times \frac{1\; {\text{hour}}}{60\; \text{minute}} \\ &= \frac{49}{15}\; \text{hour} \end{aligned}$ .

Calculate average speed of each train:

$\begin{aligned}v(\text{BOS $\to$ NYC}) &= \frac{s}{t}\\ &= \frac{221\; \text{mile}}{\displaystyle \frac{11}{3}\; \text{hour}} \\ &= \frac{663}{11}\; \text{mile} \cdot \text{hour}^{-1}\end{aligned}$ .

$\begin{aligned}v(\text{NYC $\to$ BOS}) &= \frac{s}{t}\\ &= \frac{221\; \text{mile}}{\displaystyle \frac{49}{15}\; \text{hour}} \\ &= \frac{2652}{49}\; \text{mile} \cdot \text{hour}^{-1}\end{aligned}$

Assume that it takes a time period of $t$ for the trains to pass by each other after departure. Distance each train travelled would be:

$s(\text{NYC $\to$ BOS}) = v(\text{NYC $\to$ BOS})\, t$ .

$s(\text{BOS $\to$ NYC}) = v(\text{BOS $\to$ NYC})\, t$ .

Since the trains have just passed by each other, the sum of the two distances should be equal to the distance between the stations:

$v(\text{NYC $\to$ BOS})\, t + v(\text{BOS $\to$ NYC})\, t = 221\; \text{mile}$ .

Rearrange and solve for $t$ :

$(v(\text{NYC $\to$ BOS}) + v(\text{BOS $\to$ NYC}))\, t = 221\; \text{mile}$ .

$\begin{aligned}t &= \frac{221\; \text{mile}}{v(\text{NYC $\to$ BOS}) + v(\text{BOS $\to$ NYC})} \\ &= \frac{221\; \text{mile}}{\displaystyle \frac{663}{11}\; \text{mile} \cdot \text{hour}^{-1} + \frac{2652}{49}\; \text{mile} \cdot \text{hour}^{-1}} \\ &= \frac{539}{279}\; \text{hour}\end{aligned}$ .

Distance each train travelled in $t = (539 / 279)\; \text{hour}$ :

$\begin{aligned}s(\text{BOS $\to$ NYC}) &= v\, t \\ &= \frac{663}{11}\; \text{mile} \cdot \text{hour}^{-1} \times \frac{539}{279}\; \text{hour} \\ &\approx 116\; \text{mile}\end{aligned}$ .

$\begin{aligned}s(\text{NYC $\to$ BOS}) &= v\, t \\ &= \frac{2652}{49}\; \text{mile} \cdot \text{hour}^{-1} \times \frac{539}{279}\; \text{hour} \\ &\approx 105\; \text{mile} \end{aligned}$ .

8 0

2 years ago

Which of the following is most likely to be attracted to a magnet?

Naya [18.7K]

Answer:

Explanation:

because it is made out of metel

7 0

3 years ago

Imagine That Kevin can instantly transport himself between Planet X and planet Y. Which statement could be said about Kevin in t

Svetradugi [14.3K]

When Kevin pulls off this stunt, his average speed is (distance) / (time).

So, whatever the distance may be, his average speed for the trip is

(some distance)/0 = infinite speed.

Now, stay with me here:

His acceleration at the beginning of the trip is

(change in speed) / (time to change)

Whatever speed he started at, his acceleration had to be

(infinite change in speed)/(no time).

That's a big acceleration doncha know.

He needed an infinite force and an infinite amount of energy from somewhere to achieve that acceleration, and as soon as he started accelerating, his insides got totally shredded.

Whatever arrived on Planet-Y looked like a pile of overcooked pasta.

It wasn't worth the trip.

7 0

3 years ago