He used truffula trees to make thneeds
Answer:
Entropy is increasing. Entropy is decreasing.
Explanation:
The Entropy doesn't change.
Answer:
Explanation:
Given that,
Radius, r = 2 m
Velocity, v = 1 m/s
We need to find the magnitude of the centripetal acceleration. The formula for the centripetal acceleration is given by :
So, the magnitude of centripetal acceleration is .
Answer:
a. b. c. d. The angular acceleration when sitting in the middle is larger.
Explanation:
a. The magnitude of the torque is given by , being r the radius, F the force aplied and the angle between the vector force and the vector radius. Since and so .
b. Since the relation hols, being I the moment of inertia, the angular acceleration can be calculated by . Since we have already calculated the torque, all left is calculate the moment of inertia. The moment of inertia of a solid disk rotating about an axis that passes through its center is , being M the mass of the disk. If we assume that a person has a punctual mass, the moment of inertia of a person would be given by , being the mass of the person and the distance from the person to the center. Given all of this, we have
.
c. Similar equation to b, but changing , so
.
d. The angular acceleration when sitting in the middle is larger because the moment of inertia of the person is smaller, meaning that the person has less inertia to rotate.
Answer:
Trial 1 is the largest, trial 3 is the smallest
Explanation:
Given:
<em>Trial 1</em>
M₁ = 6·10²² kg
d₁ = 3 500 km = 3.5·10⁶ м
<em>Trial 2</em>
M₂ = 6·10²² kg
d₂ = 7 000 km = 7·10⁶ м
<em>Trial 3</em>
M₃ = 3·10²² kg
d₃ = 7 000 km = 7·10⁶ м
___________
F - ?
Gravitational force:
F₁ = G·m·M₁ / d₁² = m·6.67·10⁻¹¹·6·10²² / (3.5·10⁶)² = 0.37·m (N)
F₂ = G·m·M₂ / d₂² = m·6.67·10⁻¹¹·6·10²² / (7·10⁶)² = 0.08·m (N)
F₃ = G·m·M₃ / d₃² = m·6.67·10⁻¹¹·3·10²² / (7·10⁶)² = 0.04·m (N)
Trial 1 is the largest, trial 3 is the smallest