Answer:
-0.045 N, they will attract each other
Explanation:
The strength of the electrostatic force exerted on a charge is given by
where
q is the magnitude of the charge
E is the electric field magnitude
In this problem,
(negative because inward)
So the strength of the electrostatic force is
Moreover, the charge will be attracted towards the source of the electric field. In fact, the text says that the electric field points inward: this means that the source charge is negative, so the other charge (which is positive) is attracted towards it.
Answer:
Number of electrons, 
Explanation:
It is given that,
Resistance, R = 4 ohms
Current, I = 3 A
Time, t = 5 min = 300 s
We need to find the number of electrons pass through the resistor during this time interval. Let the number of electron is n.
i.e. q = n e ...............(1)
And current, 
e is the charge of an electron
So, the number of electrons pass through the resistor is 
. Hence, this is the required solution.
Answer:
400000
Explanation:
So first solve one part:
(3.25 * 10^5)
(3.25 * 100,000)
= 325000
Then solve the next part:
(7.5 * 10^4)
(7.5 * 10000)
= 75000
Now lastly, add the two answers:
325000 + 75000 = 400000
Therefore,
(3.25 x 10^5) + (7.5 x 10^4) = 400000
Pressure = Force / Area
Put your data in front of yourself.
Force = 600 Newtons
Area = 300 cm^2
Firstly you need to convert the area into m^2 and you do this by diving 300 with 10000.
Now you use the formula:-
Pressure = 600/ 0.03
Which comes out to be 20,000 Pa.
Hope this helps!
<span>For this particular problem, we use Ohm's Law. This law deals with the relation between
voltage and current in an ideal conductor. It states that: Potential difference
across a conductor is proportional to the current that pass through it. It is
expressed as V=IR. Using the equation, we can isolate I or the current to one side and the other terms to the other side. We calculate as follows:
V = IR
I = V/R
I = 12 V / 20 </span><span>Ω
I = 0.6 amperes
Therefore, the current that is flowing through the wire supplied with 12 V and having a resistance of 20 </span><span>Ω would be 0.6 amperes.</span>
