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3 years ago

Explain what nuclear fusion is in the role it plays in Stars. DO NOT LOOK UP ANSWERS

Physics

1 answer:

Aloiza [94]3 years ago

8 0

Answer:

Stars are powered by nuclear fusion in their cores, mostly converting hydrogen into helium. The production of new elements via nuclear reactions is called nucleosynthesis. A star's mass determines what other type of nucleosynthesis occurs in its core (or during explosive changes in its life cycle).

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The blackbody radation emmitted from a furnace peaks at a wavelength of 1.9 x 10^-6 m (0.0000019 m). what is the temperature ins

krek1111 [17]

Answer:

Temperature, T = 1542.10 K

Explanation:

It is given that,

The black body radiation emitted from a furnace peaks at a wavelength of, $\lambda=1.9\times 10^{-6}\ m$

We need to find the temperature inside the furnace. The relationship between the temperature and the wavelength is given by Wein's law i.e.

$\lambda\propto \dfrac{1}{T}$

$\lambda=\dfrac{b}{T}$

b = Wein's displacement constant

$\lambda=\dfrac{2.93\times 10^{-3}}{T}$

$T=\dfrac{2.93\times 10^{-3}}{\lambda}$

$T=\dfrac{2.93\times 10^{-3}}{1.9\times 10^{-6}\ m}$

T = 1542.10 K

So, the temperature inside the furnace is 1542.10 K. Hence, this is the required solution.

3 0

3 years ago

The company where you work has obtained and stored five lasers in a supply room. You have been asked to determine the intensity

VikaD [51]

Answer:

a) I = 5.79 10⁵ W/m² , b) I = 2.58 10² W / m², c) I = 8.03 10³ W / m² , d) I = 5.3 10⁶ W / m², e) I = 9 10¹ W / m² , f) D> A> C> B> E

Explanation:

The intensity is defined as the power per unit area

I = P / A

The area of a circle is

A = π r²

Laser A

Power P = 2.2 W

Diameter d = 2.9 mm = 2.9 10⁻³ m

Let's calculate

Area

A = π d² / 4

A = π (2.2 10⁻³)²/4

A = 3.80 10⁻⁶ m²

Let's calculate the intensity

I = 2.2 / 3.80 10⁻⁶

I = 0.579 10⁶ W / m²

I = 5.79 10⁵ W/m²

Laser B

The electric field is E = 440 V / m

Intensity average is

I = E B / 2 μ₀

The relationship of the fields with the speed of light

E / B = c

The intensity

I = EE / 2 μ₀ c

I = 440² / (2 4π 10⁻⁷ 3 10⁸)

I = 1.936 105/750

I = 2.58 10² W / m²

Laser C

The magnetic field amplitude B = 8.2 10⁻⁶ T

I = c / 2μ₀ B²

I = 3 10⁸/2 4π 10⁻⁷ (8.2 10⁻⁶)²

I = 8.03 10³ W / m²

Part D

Diameter d = 1.8 mm = 1.8 10⁻³ m

The radius is r = d / 2 = 0.9 10⁻³ m

The force is F = 9.0 10⁻⁸ N

The radiation pressure is on a reflective surface is

P = 2S / c

I = S =P c / 2

The definition of pressure is

P = F / A

I = F c / 2 A

I = 9.0 10⁻⁸ 3 10⁸ / (2π (0.9 10⁻³)²)

I = 5.3 10⁶ W / m²

Part E

Average energy density

u = 3.0 10⁻⁷ J / m³

I = S = c u

I = 3 10⁸ 3.0 10⁻⁷

I = 9 10¹ W / m²

Part F

Sort in descending order

The order is

D> A> C> B> E

7 0

3 years ago

When two kinds of pulleys are used together the system is called

jekas [21]

They are called fixed and movable pulleys

3 0

3 years ago

Compare the gravitational force the sun exerts on Earth to the gravitational force Earth exerts on the sun.

podryga [215]

Answer:

Mass of sun > Mass of earth

Therefore, the sun will exert more gravitational force on earth.

Explanation:

While comparing the gravitational force exerted by two objects, we need to observe which object has a greater mass.

The object with the greater mass exerts a more gravitational force on the other object.

We know that mass of the sun is about 1.99 x 10³⁰ kg, and the earth's mass is only 6.0 x 10²⁴.

Mass of sun > Mass of earth

Therefore, the sun will exert more gravitational force on earth.

7 0

3 years ago

Acceleration is defined as a change in velocity over time. If a runner increases velocity

Anton [14]

Answer:

a = 0,1[m/s^2]

Explanation:

First we need to indentify the initial data.

And using this kinematic equation we have:

$v = 4[m/s]\\v_{0}= 2 [m/s] \\t = 20[s]\\\\v= v_{0}+a*t\\a=\frac{v-v_{0}}{t} \\a= \frac{4-2}{20} \\a=0.1[m/s^{2}]$

8 0

4 years ago

Explain what nuclear fusion is in the role it plays in Stars. DO NOT LOOK UP ANSWERS​

Explain what nuclear fusion is in the role it plays in Stars. DO NOT LOOK UP ANSWERS