All categories

2 years ago

In the reaction: CH3COO-+NH4+----------CH3COOH+NH3 what is the reactant acid and its conjugate base?

Chemistry

1 answer:

WINSTONCH [101]2 years ago

8 0

Answer : The reactant acid and conjugate base in this reaction is, $NH_4^$ and $NH_3$ .

Explanation :

Conjugate acid : A species that is formed by receiving of a proton $(H^+)$ by a base is known as conjugate acid.

Conjugate base : A species that is formed by donating of a proton by an acid is known as conjugate base.

The given chemical reaction is,

$CH_3COO^-+NH_4^+\rightleftharpoons CH_3COOH+NH_3$

In this reaction, $CH_3COO^-$ (base) react with $NH_4^$ (acid) to give $CH_3COOH$ (conjugate acid) and $NH_3$ (conjugate base).

Therefore, the reactant acid and conjugate base in this reaction is, $NH_4^$ and $NH_3$ .

You might be interested in

How many liters of water would you need to add to 4.36 moles of NaCl to create a 9.4 M solution?

marishachu [46]

Answer:

0.464 L

Explanation:

Molarity (M) = number moles (n) ÷ volume (V)

According to the information given in this question:

number of moles (n) = 4.36 moles

Molarity = 9.4M

Volume = ?

Using M = n/V

9.4 = 4.36/V

9.4V = 4.36

V = 4.36/9.4

V = 0.464 L

Hence, 0.464L of water are needed the volume of water.

3 0

3 years ago

Select True or False: Hydrogen plays an important role in many industrial processes. The following correctly represents a balanc

Orlov [11]

Answer: False

Explanation:

Since the given equation is not balanced properly.

Since oxygen and hydrogen atoms are not balanced.

There should be 6 H2O (g) molecules and 14 mol H2 (g)

5 0

2 years ago

34. An electron in the 3d state of the hydrogen atom has a radial part of the wave function of the form A r2 exp(-r/3ao). What i

nikdorinn [45]

Answer: Option (e) is the correct answer.

Explanation:

Formula to calculate radius is as follows.

p(r) = $Ar(r^{2}e^{\frac{-r}{3a_{o}}}$

= $Ar^{3}e^{\frac{-r}{3a_{o}}}$

$\frac{dp(r)}{dr}$ = 0

$Ar^{3}e^{\frac{-r}{3a_{o}}}(\frac{-1}{3a_{o}}$ + $Ae^{\frac{-r}{3a_{o}}}(3r^{2})$ = 0

$\frac{Ar^{3}}{3a_{o}}e^{\frac{-r}{3a_{o}}}$

= $3Ar^{2}e^{\frac{-r}{3a_{o}}}$

r = $9a_{o}$

Thus, we can conclude that most likely radius at which the electron would be found is $9a_{o}$ .

4 0

3 years ago

Please help ASAP I’ll make you u as brainlister please 100 points pelaseee

inessss [21]

Answer:

Explanation:

6 0

3 years ago

Read 2 more answers

The combustion of 135 mg of a hydrocarbon produces 440 mg of CO2 and 135 mg H2O. The molar mass of the hydrocarbon is 270 g/mol.

NeX [460]

Answer:

Molecular formula = C20H30

Explanation:

NB 440mg = 0.44g, 135mg= 0.135g

From the question, moles of CO2= 0.44/44= 0.01mol

Since 1 mol of CO2 contains 1mol of C, it implies mol of C = 0.01

Also from the question, moles of H2O = 0.135/18= 0.0075mole

Since 1 mol of H2O contains 2mol of H, it implies mol of H = 0.0075×2= 0.015 mol of H

To get the empirical formula, divide by smallest number of mole

Mol of C = 0.01/0.01=1

Mol of H = 0.015/0.01= 1.5

Multiply both by 2 to obtain a whole number

Mol of C =1×2 = 2

Mol of H= 1.5×2 = 3

Empirical formula= C2H3

[C2H3] not = 270

[ (2×12) + 3]n = 270

27n = 270

n=10

Molecular formula= [C2H3]10= C20H30

5 0

3 years ago