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Ad libitum [116K]
2 years ago
8

In the reaction: CH3COO-+NH4+----------CH3COOH+NH3 what is the reactant acid and its conjugate base?

Chemistry
1 answer:
WINSTONCH [101]2 years ago
8 0

Answer : The reactant acid and conjugate base in this reaction is, NH_4^ and NH_3.

Explanation :

Conjugate acid : A species that is formed by receiving of a proton (H^+) by a base is known as conjugate acid.

Conjugate base : A species that is formed by donating of a proton by an acid is known as conjugate base.

The given chemical reaction is,

CH_3COO^-+NH_4^+\rightleftharpoons CH_3COOH+NH_3

In this reaction, CH_3COO^-(base) react with NH_4^(acid) to give CH_3COOH(conjugate acid) and NH_3(conjugate base).

Therefore, the reactant acid and conjugate base in this reaction is, NH_4^ and NH_3.

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How many liters of water would you need to add to 4.36 moles of NaCl to create a 9.4 M solution?
marishachu [46]

Answer:

0.464 L

Explanation:

Molarity (M) = number moles (n) ÷ volume (V)

According to the information given in this question:

number of moles (n) = 4.36 moles

Molarity = 9.4M

Volume = ?

Using M = n/V

9.4 = 4.36/V

9.4V = 4.36

V = 4.36/9.4

V = 0.464 L

Hence, 0.464L of water are needed the volume of water.

3 0
3 years ago
Select True or False: Hydrogen plays an important role in many industrial processes. The following correctly represents a balanc
Orlov [11]

Answer: False

Explanation:

Since the given equation is not balanced properly.

Since oxygen and hydrogen atoms are not balanced.

There should be 6 H2O (g) molecules and 14 mol H2 (g)

5 0
2 years ago
34. An electron in the 3d state of the hydrogen atom has a radial part of the wave function of the form A r2 exp(-r/3ao). What i
nikdorinn [45]

Answer: Option (e) is the correct answer.

Explanation:

Formula to calculate radius is as follows.

          p(r) = Ar(r^{2}e^{\frac{-r}{3a_{o}}}

                = Ar^{3}e^{\frac{-r}{3a_{o}}}

     \frac{dp(r)}{dr} = 0

            Ar^{3}e^{\frac{-r}{3a_{o}}}(\frac{-1}{3a_{o}} + Ae^{\frac{-r}{3a_{o}}}(3r^{2}) = 0

                     \frac{Ar^{3}}{3a_{o}}e^{\frac{-r}{3a_{o}}}

                      = 3Ar^{2}e^{\frac{-r}{3a_{o}}}

                       r = 9a_{o}

Thus, we can conclude that most likely radius at which the electron would be found is 9a_{o}.

4 0
3 years ago
Please help ASAP I’ll make you u as brainlister please 100 points pelaseee
inessss [21]

Answer:

(C) im pretty sure is the answer

Explanation:

6 0
3 years ago
Read 2 more answers
The combustion of 135 mg of a hydrocarbon produces 440 mg of CO2 and 135 mg H2O. The molar mass of the hydrocarbon is 270 g/mol.
NeX [460]

Answer:

Molecular formula = C20H30

Explanation:

NB 440mg = 0.44g, 135mg= 0.135g

From the question, moles of CO2= 0.44/44= 0.01mol

Since 1 mol of CO2 contains 1mol of C, it implies mol of C = 0.01

Also from the question, moles of H2O = 0.135/18= 0.0075mole

Since 1 mol of H2O contains 2mol of H, it implies mol of H = 0.0075×2= 0.015 mol of H

To get the empirical formula, divide by smallest number of mole

Mol of C = 0.01/0.01=1

Mol of H = 0.015/0.01= 1.5

Multiply both by 2 to obtain a whole number

Mol of C =1×2 = 2

Mol of H= 1.5×2 = 3

Empirical formula= C2H3

[C2H3] not = 270

[ (2×12) + 3]n = 270

27n = 270

n=10

Molecular formula= [C2H3]10= C20H30

5 0
3 years ago
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