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maw [93]
4 years ago
5

It is found that when one mole of sodium acetate trihydrate (nac2h302 3h2o, fw 136.08 g/mol) was heated to 58oc, water of hydra

tion was released.
Chemistry
1 answer:
Nataly [62]4 years ago
4 0
<span>Hydration can occur when one mole of sodium acetate trihydrate is heated. Sodium acetate or NaC2H3O2 3H2O contains three water molecules within each unit in the crystal. The corresponding amount of hydration energy is already released when sodium acetate absorbs water and is then converted to sodium acetate trihydrate.</span>
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Why do elements that make positive ions occur on the left side of the periodic table while those that make negative ions occur o
Lynna [10]

Answer:

Elements in the same group have the same number of valence electrons.

Explanation: Science.

8 0
3 years ago
Calculate the theoretical atom economy for each reaction.
Arisa [49]
100% find the gfm of both sides then divide 
4 0
3 years ago
1) How much energy would be required to melt 15.0 g of ice at 0°C?
DerKrebs [107]

Answer:

5010J

Explanation:

The following data were obtained from the question:

Mass (m) = 15g

Heat of fusion (ΔHf) = 334J/g

Heat required (Q) =..?

The heat energy required to melt the ice can be obtained as follow:

Q = m·ΔHf

Q = 15 x 334

Q = 5010J

Therefore, the heat energy required to melt the ice is 5010J.

8 0
3 years ago
When the amount of oxygen is limited, carbon and oxygen react to form carbon monoxide. How many grams of CO can be formed from 3
Alinara [238K]

<u>61.25 grams</u> of CO can be formed from 35 grams of oxygen.

The molecular mass of oxygen is <u>16 gmol⁻¹</u>

The molecular mass of carbon monoxide is<u> 28 gmol⁻¹</u>

Explanation:

The molar mass of carbon monoxide is molar mass of C added to that of O;

12 + 16 = 28

= 28g/mol

The molar mass of oxygen is 16 g/mol while that of oxygen gas (O₂) is 32 g/mol

Since the ration oxygen to carbon monoxide is 1: 2 moles, we begin to find out how many moles of carbon monoxide are formed by 35 g of oxygen;

35/32 * 2

= 70/32 moles

Then multiply by the molar mass of carbon monoxide;

70/32 * 28

= 61.25 g

4 0
3 years ago
The K w for water at 0 ∘ C is 0.12 × 10 − 14 M 2 . Calculate the pH of a neutral aqueous solution at 0 ∘ C . p H = Is a pH = 7.2
Karo-lina-s [1.5K]

Answer:

pH → 7.46

Explanation:

We begin with the autoionization of water. This equilibrium reaction is:

2H₂O  ⇄   H₃O⁺  +  OH⁻            Kw = 1×10⁻¹⁴         at 25°C

Kw = [H₃O⁺] . [OH⁻]

We do not consider [H₂O] in the expression for the constant.

[H₃O⁺] = [OH⁻] = √1×10⁻¹⁴   →  1×10⁻⁷ M

Kw depends on the temperature

0.12×10⁻¹⁴ = [H₃O⁺] . [OH⁻]  → [H₃O⁺] = [OH⁻]         at 0°C

√0.12×10⁻¹⁴ = [H₃O⁺] → 3.46×10⁻⁸ M

- log [H₃O⁺] = pH

pH = - log 3.46×10⁻⁸ → 7.46

8 0
3 years ago
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