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rusak2 [61]
3 years ago
7

Under the right conditions aluminum will react with chlorine to produce aluminium chloride.

Chemistry
1 answer:
Andreas93 [3]3 years ago
5 0

Answer:

Ok

The Limiting reagent is Aluminum. Its not in excess. So the reaction ends once its exhausted. So all Aluminum will be used up

From the question ....

157g of Al

Find the number if reacting Moles...

M=mass/molar mass

M= 157/27

=5.81moles of Aluminum is reacting.

Now looking at the equation of reaction(Always make sure its balanced)...

2moles of Al react to produce 2 Moles of AlCl3

Their Mole ratio is equal

Since their Mole ratio is equal 2:2.... That means... That 5.81moles of AlCl3 would be produced because the mole of Al is 5.81

So We now know the Moles of AlCL3 produced

getting the Mass won't be difficult.

Again

Mole=Mass/Mm

Mass = Mole x Mm(Molar Mass)

Mass of AlCl3 = 5.81 x (27 + 35.5x3)

Note: The arithmetic done in the parenthesis is the molar mass of AlCl3

Mass of AlCl3 = 5.81 x 133.5

=775.63g of AlCl3.

Have a great Day!!!!

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Answer:

\boxed{3}

Explanation:

The Rydberg equation gives the wavelength λ for the transitions:

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where

R= the Rydberg constant (1.0974 ×10⁷ m⁻¹) and

\text{$n_{i}$ and $n_{f}$ are the numbers of the energy levels}

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n_{f} = 2

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Calculation:  

\begin{array}{rcl}\dfrac{1}{657 \times 10^{-9}} & = & 1.0974 \times 10^{7}\left ( \dfrac{1}{2^{2}} - \dfrac{1}{n_{f}^{2}} \right )\\\\1.522 \times 10^{6} &= &1.0974\times10^{7}\left(\dfrac{1}{4} - \dfrac{1}{n_{f}^{2}} \right )\\\\0.1387 & = &\dfrac{1}{4} - \dfrac{1}{n_{f}^{2}} \\\\-0.1113 & = & -\dfrac{1}{n_{f}^{2}} \\\\n_{f}^{2} & = & \dfrac{1}{0.1113}\\\\n_{f}^{2} & = & 8.98\\n_{f} & = & 2.997 \approx \mathbf{3}\\\end{array}\\\text{The value of $n_{i}$ is }\boxed{\mathbf{3}}

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3 years ago
23.9 km + 15 km
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Answer:

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4 0
3 years ago
Please I need help on these 3 questions. Thank You.​
Liula [17]

1.

V = 200 mL (volume)

c = 3 M = 3 mol/L (concentration)

First we convert mL to L:

200 mL = 0.2 L

Then we calculate the moles using the formula: n = V × c = 0.2 L × 3 mol = 0.6 mol

Finally, we just use the molar mass of CaF2 to calculate the actual mass:

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The formula is: m = n × mm (mass = moles × molar mass)

m = 0.6 mol × 78 g/mol = 46.8 g

2.

For this question the steps are exactly like the first question.

V = 50mL = 0.05 L

c = 12 M = 12 mol/L

n = V × c = 0.05 L × 12 mol/L = 0.6 mol

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3.

The steps for this question are the opposite way.

m(K2CO3) = 250 g

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n = m ÷ mm = 1.81 mol

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If scientists want to determine if a skin cream is effective against fighting acne, what would be the independent variable?
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Answer:skin cream

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the independent variable is the variable that is always changed or manipulated. in this case the skin cream is the independent variable.

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Rank the following particles, from largest to smallest in mass: alpha particle, beta particle, proton.
Len [333]
The best and most correct answer among the choices provided by your question is the fourth choice.

The correct arrangement of these particles from largest to smallest mass is: <span>proton, alpha particle, beta particle.</span>

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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