Answer: 30:5
Step-by-step explanation:
Five levels were beaten so thirty levels are left so whats left to what’s beaten is 30:5
A 90 degree counter-clockwise rotation is being done on the black figure to get the red figure.
The algebraic rule for a 90 degree counter-clockwise rotation is 
For instance, the point C = (0,1) moves to C' = (-1,0), which is shown in the graph given and also you can use the rule above to get the same coordinates. The other points A,B and D follow the same rule.
Side note: the rotation is centered at the origin (0,0). This point is fixed.
The longest line segment that can be drawn in a right rectangular prism that is 14cm long, 13cm wide and 11cm tall is 19.1cm.
<h3>What is a right rectangular prism?</h3>
A right rectangular prism is a three dimensional solid shape formed by 6 rectangles.
it is also called the cuboid.
Analysis:
The diagonal of the face of the prism with dimensions 14cm long and 13cm wide is the longest line segment that can be drawn.
Since rectangles have 90° on each vertex, we can use Pythagoras theorem to calculate for the length of the diagonal.
=
+ 
=
+ 
= 196 + 169 = 365
= 365
diagonal =
= 19.1cm
In conclusion, the length of the longest diameter is 19.1cm
Learn more about Right rectangular prism: brainly.com/question/3317747
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Answer:
A bus can carry 22 students and a van can carry 11 students.
Step-by-step explanation:
Let the number of students bus can carry be 'b'.
Let the number of students van can carry be 'v'.
Given:
One High school:
Number of bus = 6
Number of vans = 5
Number of students = 187
So we can say that;
Number of bus multiplied by number of students bus can carry plus Number of vans multiplied by number of students van can carry is equal to Number of students.
framing in equation form we get;
⇒ Equation 1
Also Given:
One High school:
Number of bus = 7
Number of vans = 2
Number of students = 176
So we can say that;
Number of bus multiplied by number of students bus can carry plus Number of vans multiplied by number of students van can carry is equal to Number of students.
framing in equation form we get;
⇒ Equation 2
Now multiplying equation 2 by 5 we get;

⇒ Equation 3
Now multiplying Equation 1 by 2 we get;

⇒ Equation 4
Subtracting equation 4 from equation 3 we get;

Substituting value of b in equation 2 we get;

Hence A bus can carry 22 students and a van can carry 11 students.
5 x 1/4 = 1 1/4 or 1.25
4 x 1/2 = 2
1.25 + 2 = 3.25 or 3 and 1/4