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kobusy [5.1K]
3 years ago
9

Complete the name of the following polynomial: 23 + 4x3 __________ binomial

Mathematics
1 answer:
elena55 [62]3 years ago
3 0
<span>I'm pretty sure that the following polynomial 23 + 4x3 is a cubic binomial.</span>
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David, Stephen and June share £96 in a ratio 2:3:3. How much money does each person get
AveGali [126]

Answer:

<u>David gets £24, Stephen gets £36, and June gets £36.</u>

Step-by-step explanation:

Firstly, add the ratio values together.

2:3:3  ⇒  2 + 3 + 3 = 8

Next, divide £96 (your total) by 8.

£96 ÷ 8 = £12

Now, we have the number of pounds for 1 value.

Multiply 12 by each ratio value.

<u>12 × </u><u>2</u> : <u>12 × </u><u>3</u> : <u>12 × </u><u>3</u>

= 24:36:36

Therefore, David gets £24, Stephen gets £36, and June gets £36.

<em />

<em>I hope this helped! I would really appreciate it if you would please mark me brainliest! Have a blessed day!</em>

7 0
3 years ago
Read 2 more answers
Find the value of (a+b)^2 if a^2+b^2=10 and ab=3
seropon [69]

Answer:

(a+b)^2 if a©+2b

Step-by-step explanation:

i not sure

6 0
3 years ago
Read 2 more answers
Verify cot x sec^4x=cotx +2tanx +tan^3x
Tanzania [10]

Answer:

See explanation

Step-by-step explanation:

We want to verify that:

\cot(x)  \:  { \sec}^{4} x =  \cot(x) + 2 \tan(x)   +  { \tan}^{3} x

Verifying from left, we have

\cot(x)  \:  { \sec}^{4} x  = \cot(x)  \: ( 1 +  { \tan}^{2} x )^{2}

Expand the perfect square in the right:

\cot(x)  \:  { \sec}^{4} x  = \cot(x)  \: ( 1 +  { 2\tan}^{2} x  + { \tan}^{4} x)

We expand to get:

\cot(x)  \:  { \sec}^{4} x  = \cot(x)  \:   +  \cot(x){ 2\tan}^{2} x  +\cot(x) { \tan}^{4} x

We simplify to get:

\cot(x)  \:  { \sec}^{4} x  = \cot(x)  \:   +  2 \frac{ \cos(x) }{\sin(x) ) }  \times  \frac{{ \sin}^{2} x}{{ \cos}^{2} x}   +\frac{ \cos(x) }{\sin(x) ) }  \times  \frac{{ \sin}^{4} x}{{ \cos}^{4} x}

Cancel common factors:

\cot(x)  \:  { \sec}^{4} x  = \cot(x)  \:   +  2 \frac{{ \sin}x}{{ \cos}x}   +\frac{{ \sin}^{3} x}{{ \cos}^{3} x}

This finally gives:

\cot(x)  \:  { \sec}^{4} x =  \cot(x) + 2 \tan(x)   +  { \tan}^{3} x

3 0
3 years ago
Plz help me w this !!
larisa [96]

Answer:

sum of angles in atriangle=180°

Step-by-step explanation:

w-45°+w-37°+w+19°=180°(sum of angles in a triangle)

3w=180°+45°+37°-19°

3w=243°

w=81°

7 0
3 years ago
I need help pls I only have 3 mins!!
KatRina [158]

Answer:

First one is 6 16/21

Second one is 3 14/15

Step-by-step explanation:

3 0
3 years ago
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