Answer:
Decreasing the concentration of N2O3
Explanation:
This is because the products on the right of the reaction occupy more space. One (1) mole of NO and another mole of NO2 will occupy more space than the one (1) mole of N2O3. Therefore decreasing the concentration of N2O3 will shift the reaction to the right because the products will have more space to occupy – hence favoring equilibrium.
The correct equation
for the overall reaction can simply be obtained by adding the two separate
equations together. Now when you add the two equations together, the overall K can
be calculated by multiplying the individual K values. Therefore:<span>
K(overall) = K1 * K2 </span>
K(overall) = (1.6 x
10^-10) * (1.5 x 10^7)
<span>K(overall) = 2.4 x
10^-3</span>
Answer:
Hello There!!
Explanation:
I believe the answer is nuclear.
hope this helps,have a great day!!
~Pinky~
STRUCTURE OF BROMOUS ACID: H–O–Br=O
<span>In this structure, all the elements have a formal charge of
zero. The formal charge of each element is calculated below: </span><span>
H: 1 – 1/2(2) – 0 = 0
O: 6 – 1/2(4) – 4 = 0
Br: 7 – 1/2(6) – 4 = 0
<span>O: 6 – 1/2(4) – 4 = 0</span></span>
