Question

A Ca atom (atomic number = 20) is in the ground state. Light is shined on the atom, exciting the most energetic electron. Which of the following are possible quantum numbers (n,l,m) of this excited electron? We omit the electron spin quantum number

Answer 1

Answer:

The possible quantum numbers for Ca atom when it is in excited

n = 4

l= 1

m =-1,0,1

Explanation:

Given that,

Atomic number = 20

The configuration of Ca

$Ca = 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2$

So, The principle quantum number is n =4.

The azimuthal quantum number can take value from 0,1,2...(n-1)

In the ground state, l= 0

When it is excited to p state

Then, l = 1

The magnetic quantum number can take value from l to -l

$m=1,0,-1$

Hence, The possible quantum numbers for Ca atom when it is in excited

n = 4

l= 1

m =-1,0,1