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pav-90 [236]
3 years ago
13

What are the units for impulse? m/s Kg Ns Newtons

Physics
1 answer:
Elodia [21]3 years ago
7 0

Answer:

Kg.m/s is the unit for impulse

Explanation:

If i were wrong please correct me.

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Answer:wdym insulation if u mean like covering than the ppls heads

Explanation:

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4 years ago
Most of the mass of the milky way exists in the form of.
Andrews [41]

Answer: Dark matter.

Explanation: Hope it helps :)

7 0
3 years ago
Read 2 more answers
Please help me I will give you 20 points !!
nadezda [96]

Answer:

D. The primary source, because it was written by the researcher

Explanation:

One should learn to trust the primary source more because it is the real work of the researcher.

A primary work defines the work of research from his or her experimental findings.

  • The primary source presents experimental data and other subordinates ones to reach a conclusion as seen from the view of the researcher.
  • A secondary source implies someone else documenting their own opinion about the primary experimental set up.
  • This can get dicey in the sense that results can be twisted to serve other ulterior motives.

8 0
3 years ago
An aluminum calorimeter with a mass of 100 g contains 250 g of water. The calorimeter and water are in thermal equilibrium at 10
Nadya [2.5K]

Answer:

1822.14 J/kg C

Explanation:

Mass of aluminum  = 0.100 kg

Mass of Water = 0.250 kg

Mass of copper = 0.300 kg

Mass of unknown object = 0.70 kg

Initial temperature of Aluminum = 10 C

Initial  temperature  of water = 10 C

Initial temperature of copper = 30 C

Initial temperature of = 100 C

Final temperature of all substances = 20 C

Change in temperature of each  of them Aluminum, water , copper and unknown material  respectively = 10 C , 10 C , -10 C, -80 C respectively

Specific heat of  each  of them Aluminum, water , copper and unknown material  respectively = 900,4186,387 and c respectively.

Heat gained by aluminum and water = (0.1)(900)(10) + (0.250)(4186)(10) = 11365 j

heat lost by copper and unknown  material  =(0.3)(387)(-10) = -1161

heat lost by unknown  material  =  (0.070)(c)(-80) = -5.6 c

Now solve for c using the calorimetry principle.

Heat lost + Heat gained = 0

⇒ -5.6 c = -11365 - (-1161) = -10204 j

Specific heat of unknown material = - 10204 / -5.6

                                                         = 1822.14  j/kg C  

b) Material having a specific heat of 1800 j /kg C is

Polyurethane elastomer.

4 0
3 years ago
Evaluate the expression a+b when a=23 and b=45 . Write in simplest form
Viefleur [7K]
If a = 23 and b = 45

a + b = ?

23 + 45 = 68
6 0
3 years ago
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