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skad [1K]
3 years ago
6

Why is reading important in science?

Chemistry
1 answer:
Andru [333]3 years ago
7 0
<span>Dispelling the perception that Indian scientists are averse to advertising their work, recipient of this year's Shanti Swarup Bhatnagar prize, Dr.Eknath Ghate and Dr.Amol Dighe, said that in science, it is important to publish and publicise one's work globally. </span>
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In the alpha decay of Francium-221, what daughter element is produced?
aleksley [76]
<span>Astatine-217 is the daughter element produced by the alpha decay of Francium-221.</span>
8 0
3 years ago
Read 2 more answers
Enough of a monoprotic weak acid is dissolved in water to produce a 0.0118 M solution. The pH of the resulting solution is 2.32
ser-zykov [4K]

Answer:

1.94 × 10⁻³

Explanation:

Step 1: Calculate the concentration of H⁺ ions

We will use the definition of pH.

pH = -log [H⁺]

[H⁺] = antilog -pH = antilog -2.32 = 4.79 × 10⁻³ M

Step 2: Calculate the acid dissociation constant (Ka) of the acid

For a monoprotic weak acid, whose concentration (Ca) is 0.0118 M, we can use the following expression.

Ka = [H⁺]²/Ca

Ka = (4.79 × 10⁻³)²/0.0118 = 1.94 × 10⁻³

4 0
3 years ago
If a solution has a [H+] of 9.3x10-11, what is the pH?
Rina8888 [55]

Answer:

<h2>10.03</h2>

Explanation:

The pH of a solution can be found by using the formula

pH = - log [ {H}^{+} ]

From the question we have

ph =  -  log(9.3 \times  {10}^{ - 11} )  \\  = 10.0315...

We have the final answer as

<h3>10.03</h3>

Hope this helps you

4 0
3 years ago
If 3.5 g of element X reacts with 10.5 g of element Y to form the compound XY.
irina [24]

Answer:

The percentage by mass of element X is 25 %.

The percentage by mass of element Y is 75 %

Explanation:

X + Y ⇒ XY

3.5 g of element X + 10.5 g of element Y = 14g in total

⇒Element X : 3.5g / 14g = 0.25 ⇒ x 100 % = 25 %

⇒Element Y : 10.5 / 14 = 0.75 ⇒ x 100 % = 75 %

The percentage by mass of element X is 25 %.

The percentage by mass of element Y is 75 %

8 0
3 years ago
Using molecular orbital theory, explain why the removal of one electron in O2 strengthens bonding, while the removal of one elec
Nuetrik [128]
First you have a knowledge of bond order which is
 B.O=(no. of electrons in bonding orbital - no. of electrons in non-bonding orbital)÷2  
Note:
bond strength is directly proportional to bond order.
For oxygen:
B.O=(6-2)/2= 2; after the removal of two electrons(removal occur from non-bonding orbital)
B.O=(6-0)/2= 3 (As B.O increased bond strength increased)
For Nitrogen:
B.O=(6-0)/2= 3; after the removal of two electrons(removal occur from bonding orbital)
B.O=(4-0)/2= 2 (As B.O decreased bond strength decreased)

6 0
3 years ago
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