What’s the answer???

A 4-kg ball has a momentum of 12 kg∙m/s. what is the ball's speed?

Karolina [17]

M= 4kg
v= ?
momentum = Mv
so
12kgms-¹ = 4kg×v
v= 12÷4 = 3ms-¹

7 0

3 years ago

The 3670-lb car is traveling at 25 mi/hr when the driver applies the brakes, and the car continues to move along the circular pa

Monica [59]

Answer:

$a_t = -14.37407175$

Explanation:

I was unable to submit this answer after typing it, so i create a document file that clearly shows and depicts all explanations for the question. OR

You can check the three picture slides i attached as well for the explanation.

The attached file for the document and the picture can be found below.

Download docx

5 0

3 years ago

A worker pushes horizontally on a 35.0 kg crate with a force of magnitude 112 N. The coefficient of static friction between the

OLga [1]

Answer: a) -127 N b) No. c) -112 N d) 40 N e) 15 N

Explanation:

a) Friction force always oppose to the relative movement between two surfaces, and, provided that be less than the fs max, adopt any value to counteract the applied force.

The fs max, is the horizontal component of the contact force, and can be written as follows:

Fs max = us . Fn

As the block is at rest in the vertical direction, this means that Fn must be numerically equal to the weight of the object:

Fn = m g = 35 kg. 9.8 m/s2 = 343 N → Fs max = 0.37. 343 N = 127 N

b) Now, as the applied force is smaller than Fs max, this means that the friction force, is equal and opposite to the applied forcé, i.e., -112 N, so the crate doesn´t move.

c) Please see above.

d) As explained above, the maximum friction force, is proportional to the normal force, which adopts any value needed to satisfy the Newton´s 2nd Law.

So, if we diminish the normal force, we can lower the máximum friction force, helping to the worker to move the crate.

The mínimum needed normal force, will be the one that satisfies the following:

Fs max = F applied = us Fn = 112 N = 0.37. Fn.

Solving for Fn, we get Fn= 303 N

So, the difference between the original normal force and the new one, will be the mínimum upward force needed to make the crate to move, as follows:

Fup = 343 N -303 N = 40 N

e) If we keep the normal force unchanged, but add an horizontal force to help the worker, we will need that the sum of both forces, will be equal to the Fs max, as follows:

Fh + Fapp = 127 N → Fh = 127 N – 112 N = 15 N

5 0

3 years ago

What will be the displacement of this spring if the load is 4n with a constant of 5n\m

nikdorinn [45]

As we have formula for mass spring system

F= kx ( where k is spring constant , x is displacement , F is the force acting due to load)

To find =x

So x=F/k

x= (4N) / (5N/m)

x= 0.8 m

3 0

3 years ago

What is the escape velocity on the Venus ? Venus' mass 4.90*10^ 24 kg and radius is 6.86 * 10 ^ 6 * m

gtnhenbr [62]

The escape velocity on Venus is 9761 m/s

Explanation:

The escape velocity from a planet is the speed that an object on the surface of that planet must have in order to completely escape the gravitational field of the planet.

Mathematically, it is calculated as

$v=\sqrt{\frac{2GM}{R}}$