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You are a nurse in a hospital. You are told to move a patient through three corridors each measuring 14.33 meters. Because of fr

dimulka [17.4K]

Work done by force is given by formula

$W = F.d$

now here work done against friction is given so force of friction here is

$F_f = 848 N$

It moved by three corridors with each measures

$d = 14.33 m$

so total distance will be

$s = 14.33 \times 3 = 43 m$

now from above formula of work done we will say

$W = 848 \times 43$

$W = 36464 J$

so above is the work done to move three corridors

3 0

3 years ago

PLEASE HELP !!! Which product forms from the synthesis reaction between potassium (k) and iodine (I)?

Mrrafil [7]

Answer:

Pottasium iodide (KI)

Explanation:

product of this reaction is KI. this product is an ionic compound.

8 0

3 years ago

Read 2 more answers

A bicycle travels 10 km in 20 minutes. What is its average speed (in km/h) ?

KatRina [158]

Speed= distance/time
Answer=

1,800 kilometers/hour

8 0

3 years ago

An athlete swings a ball, connected to the end of a chain, in a horizontal circle. The athlete is able to rotate the ball at the

Andrei [34K]

Answer:

a) 2nd case rate of rotation gives the greater speed for the ball

b) 1534.98 m/s^2

c) 1515.04 m/s^2

Explanation:

(a) v = ωR

when R = 0.60, ω = 8.05×2π

v = 0.60×8.05×2π = 30.34 m/s

Now in 2nd case

when R = 0.90, ω = 6.53×2π

v = 0.90×6.53×2π = 36.92 m/s

6.35 rev/s gives greater speed for the ball.

(b) a = ω^2 R = (8.05×2π)^2 )(0.60) = 1534.98 m/s^2

(c) a = ω^2 R = (6.53×2π)^2 )(0.90) = 1515.05 m/s^2

7 0

3 years ago

A 6 N and a 10 N force act on an object. The moment arm of the 6 N force is 0.2 m. If the 10 N force produces five times the tor

Levart [38]

Answer:

The moment arm is 0.6 m

Explanation:

Given that,

First force $F_{1}=6\ N$

Second force $F_{2}=10\ N$

Distance r = 0.2 m

We need to calculate the moment arm

Using formula of torque

$\tau=Force\times lever\ arm$

So, Here,

$\tau_{2}=5 \tau_{1}$

We know that,

The torque is the product of the force and distance.

Put the value of torque in the equation

$F_{2}\times d_{2}=5\times F_{1}\times r_{1}$

$r_{2}=\dfrac{5\times F_{1}\times r_{1}}{F_{2}}$

Where, $F_{1}$ =First force

$F_{1}$ =First force

$F_{2}$ =Second force

$r_{1}$ = distance

Put the value into the formula

$r_{2}=\dfrac{5\times6\times0.2}{10}$

$r_{2}=0.6\ m$

Hence, The moment arm is 0.6 m

6 0

4 years ago