Answer:
A)6.15 cm to the left of the lens
Explanation:
We can solve the problem by using the lens equation:
![\frac{1}{q}=\frac{1}{f}-\frac{1}{p}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bq%7D%3D%5Cfrac%7B1%7D%7Bf%7D-%5Cfrac%7B1%7D%7Bp%7D)
where
q is the distance of the image from the lens
f is the focal length
p is the distance of the object from the lens
In this problem, we have
(the focal length is negative for a diverging lens)
is the distance of the object from the lens
Solvign the equation for q, we find
![\frac{1}{q}=\frac{1}{-16.0 cm}-\frac{1}{10.0 cm}=-0.163 cm^{-1}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bq%7D%3D%5Cfrac%7B1%7D%7B-16.0%20cm%7D-%5Cfrac%7B1%7D%7B10.0%20cm%7D%3D-0.163%20cm%5E%7B-1%7D)
![q=\frac{1}{-0.163 cm^{-1}}=-6.15 cm](https://tex.z-dn.net/?f=q%3D%5Cfrac%7B1%7D%7B-0.163%20cm%5E%7B-1%7D%7D%3D-6.15%20cm)
And the sign (negative) means the image is on the left of the lens, because it is a virtual image, so the correct answer is
A)6.15 cm to the left of the lens
Answer:
f ’= 97.0 Hz
Explanation:
This is an exercise of the doppler effect use the frequency change due to the relative movement of the fort and the observer
in this case the source is the police cases that go to vs = 160 km / h
and the observer is vo = 120 km / h
the relationship of the doppler effect is
f ’= f₀ (v + v₀ / v-
)
let's reduce the magnitude to the SI system
v_{s} = 160 km / h (1000 m / 1km) (1h / 3600s) = 44.44 m / s
v₀ = 120 km / h (1000m / 1km) (1h / 3600s) = 33.33 m / s
we substitute in the equation of the Doppler effect
f ‘= 100 (330+ 33.33 / 330-44.44)
f ’= 97.0 Hz
Answer:
Explanation:
In first case we are interested in one time 6 in six rolls
Thus probability = number of chances required/Total chances
= 1/6
Similarly in the second case probability = 2/12 = 1/6
In the same way in last case probability = 100/600 = 1/6
The probability is the same . Thus all the cases has equal chances
Answer:
Light is one of nature's ways of moving energy from one place to another.
Explanation:
It has no substance, or mass. How does light travel? Light behaves like a traveling wave, something like waves in a string or on the surface of water.
Option A overweight
HOPE IT HELPS!!