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Snowcat [4.5K]
3 years ago
10

You have a normal distribution of hours per week that music students practice. The mean of the values is 8 and the standard devi

ation of the values is 4. According to the normal distribution, half of the music students practice between 5.3 to 10.7 hours each week. What percentage of the students study less than 5.3 hours each week? 12.5% 20% 25% 50%
Mathematics
1 answer:
Aleks04 [339]3 years ago
5 0

Answer:

25%

Step-by-step explanation:

Since Normal Distribution is symmetrical Distribution and 5.3 and 10.7 are both 2.7 below and 2.7 above the mean respectively.

So, % of students less than 5.3 hours per week is 25%

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Any one can help with this Venn Diagram question?.Please note that there is an another language, ignore except if you can unders
zloy xaker [14]

Answer:

(i) 30

(ii) 8

Step-by-step explanation:

Start by drawing 3 rings for the Venn diagram.  Each ring represents either Audi, BMW, or Citroën.

Next, add the information provided in the problem statement.  We know that 20 choose BMW only.  Another 20 choose Citroën only.

We know the number who choose all 3 is the same as the number that choose BMW and Citroën, but not Audi.  We'll call this number x.

Similarly, we know that the number who choose all 3 is half of those choose Audi and BMW, but not Citroën.  So we'll say that number is 2x.

We know the total number of Audi votes is 48, the total number of BMW votes is 36, and the total number of Citroën votes is 34.

Finally, we know the total number of voters is 100, including those who voted for no favorites (we'll call that number n).

We know that BMW got 36 votes, so:

20 + x + x + 2x = 36

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We know that Citroën got 34 votes, so:

20 + x + x + z = 34

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We know that Audi got 48 votes:

y + 2x + x + z = 48

y + 2(4) + 4 + 6 = 48

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Finally, we know that the total number of voters is 100.

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92 + n = 100

n = 8

8 0
3 years ago
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