We are asked to find the probability that a data value in a normal distribution is between a z-score of -1.32 and a z-score of -0.34.
The probability of a data score between two z-scores is given by formula 
.
Using above formula, we will get:
Now we will use normal distribution table to find probability corresponding to both z-scores as:
Now we will convert 
into percentage as:
Upon rounding to nearest tenth of percent, we will get:
Therefore, our required probability is 27.4% and option C is the correct choice.
I have these same questions but the way i solved them i did
A: 1/3 x 3.14 x 2*2 x 8 = 32/3 = 2000 divided by 32 = 63 scoops
The formula is 1/3 x 3.14 x r*2 x h
B: 1/3 x 3.14 x 8*2 x 8 = 128/3 = 2000 divided by 128 = 16 scoops
Help with what, unless there is a picture, my phone is glitchy and i cant see pics for sum reason
6(7 + 5) + 3 =
6(12) + 3 =
72 + 3 = 75
Considering the box and whisker plot, it is found that the number of dogs that weigh more than 35 pounds is given by:
C. 75
<h3>What does the box plot shows?</h3>
It shots the first quartile, the median and the third quartile. In this problem:
- The first quartile is of 35.
- The third quartile is of 70.
The first quartile of 35 means that 25% of the measures are less than 35, and 75% are more, hence, out of 100:
0.75 x 100 = 75
Which means that option C is correct.
More can be learned about box and whisker plots at brainly.com/question/12343132
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