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just olya [345]
2 years ago
14

The tundra is located _______.

Physics
2 answers:
Leona [35]2 years ago
8 0

Answer:

d: both north and south

Explanation:

USPshnik [31]2 years ago
4 0

Answer:

A. north of the equator is the answer.

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The free-fall acceleration at the surface of planet 1 is 26 m/s^2 . The radius and the mass of planet 2 are twice those of plane
valkas [14]

Answer:

13 m/s^2

Explanation:

The acceleration of gravity near the surface of a planet is:

g = MG / R^2

For planet 1, g = 26 m/s^2.

The gravity on planet 2 in terms of the mass and radius of planet 1 is:

g = (2M)G / (2R^2)

g = 1/2 MG / R^2

Since MG/R^2 = 26 m/s^2, then:

g = 13 m/s^2

6 0
3 years ago
Difina el concepto de salud
jeka94

Answer:bienestar mental y social. La mayoría de los padres conocen los conceptos básicos para mantener

Explanation:bienestar mental y social. La mayoría de los padres conocen los conceptos básicos para mantener a los niños sanos, como alimentarlos con alimentos saludables, asegurarse de que duerman y hagan suficiente ejercicio, y garantizar su seguridad.

5 0
3 years ago
Read 2 more answers
In the Rutherford model of hydrogen the electron (mass=9.11x10-31 kg) is in a planetary type orbit around the proton (mass=1.67x
Andrei [34K]

Answer:

(a) F_g=1.62*10^{-48}N

(b) F_e=3.68*10^{-9}N

Explanation:

(a) We use Newton's law of universal gravitation, in order to calculate the gravitational force between electron and proton:

F_g=-G\frac{m_1m_2}{r^2}

Where G is the Cavendish gravitational constant, m_1 and m_2 are the masses of the electron and the proton respectively and r is the distance between them:

F_g=-6.67*10^{-11}\frac{N\cdot m^2}{kg^2}\frac{(9.11*10^{-31}kg)(1.67*10^{-27}kg)}{(2.5*10^{-10}m)^2}\\F_g=-1.62*10^{-48}N

The minus sing indicates that the force is repulsive. Thus, its magnitude is:

F_g=1.62*10^{-48}N

(b) We use Coulomb's law, in order to calculate the electric force between electron and proton, here k is the Coulomb constant and e is the elementary charge:

F_e=-k\frac{e^2}{r^2}\\F_e=-8.99*10^{9}\frac{N\cdot m^2}{C^2}\frac{(1.6*10^{-19}C)^2}{(2.5*10^{-10}m)^2}\\F_e=-3.68*10^{-9}N

Its magnitude is:

F_e=3.68*10^{-9}N

6 0
3 years ago
Einstein's equation E=mc2 helps scientists understand the sun's energy because the equation..
scZoUnD [109]
B.

This equation quantifies the inter convertibility of mass and energy and helps us understand the large amount of energy that would be released if mass were converted to energy.<span />
7 0
3 years ago
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Is the speed of the object is zero when it's at rest ?
NARA [144]
Yes! Although the object has potential energy, the object is not moving and therefore has no speed. :)
4 0
3 years ago
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