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4 years ago

Which of the following solutions will have the lowest freezing point?

1 answer:

7 0

C. 1.0 mol/kg sodium phosphide (Na3P)<span>

This is because it will produce 4 ions, and thus has the highest molalitiy. (more particles in solution lowers the freezing point)

</span><span>remember if you ever need anything and you dont want to waste points you can just post it on my pfp or message me the question</span>

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Explain why the speed of a sled is increases as it moves down a snow -covered hill, even though no one is pushing the sled

Andrews [41]

Hope this helps you.

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3 years ago

What is electrical power and how is it measured?

Sliva [168]

Answer:

power is measured in watts and its the messure of work over time.

Explanation:

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2 years ago

An object with smaller mass and an object with a larger mass have the same kinetic energy. Which object has the higher momentum?

KatRina [158]

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object with larger mass

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3 years ago

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Marina86 [1]

To make sure the answer is correct

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3 years ago

Two identical 0.200kg mass are pressed against opposite ends of a light spring of force constant 1.75N/cm compressing the spring

arlik [135]

This type of a problem can be solved by considering energy transformations. Initially, the spring is compressed, thus having stored something called an elastic potential energy. This energy is proportional to the square of the spring displacement d from its normal (neutral position) and the spring constant k:

$E_p=\frac{1}{2}kd^2= \frac{1}{2}175\frac{N}{m}\cdot 0.37^2m^2=11.98J$

So, this spring is storing almost 12 Joules of potential energy. This energy is ready to be transformed into the kinetic energy when the masses are released. There are two 0.2kg masses that will be moving away from each other, their total kinetic energy after the release equaling the elastic energy prior to the release (no losses, since there is no friction to be reckoned with).

The kinetic energy of a mass m moving with a velocity v is given by:

$E_k = \frac{1}{2}mv^2$

And we know that the energies are conserved, so the two kinetic energies will equal the elastic potential one:

$E_p = 2E_k=mv^2$

From this we can determine the speed of the mass:

$E_p =mv^2\implies v=\pm \sqrt{\frac{E_p}{m}}=\pm\sqrt{\frac{11.98J}{0.2kg}}=\pm 7.74\frac{m}{s}$

The speed will be 7.74m/s in in one direction (+), and same magnitude in the opposite direction (-).

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3 years ago