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vlada-n [284]
4 years ago
15

Technician A says that horsepower equals the ability to perfoem work at a rate of 33,000 foot-pounds per minute. Technician B sa

ys that in many vehicles, as little as 15% of the potential energy in the fuel is delivered to the drive wheela. Who is right? Explain.
Engineering
1 answer:
DENIUS [597]4 years ago
8 0

Answer:

  Both are

Explanation:

The definition of a horsepower is 33,000 ft·lb/min, so Technician A is definitely right.

__

In many vehicles the thermal efficiency of their gasoline engine is no higher than 20%, so it is likely that Technician B is also correct. Efficiency is lower at idle and when the engine is not called upon to do much work.

(Diesel engines may have a thermal efficiency approaching 40%. Toyota has developed technology that may give some of their gasoline engines a thermal efficiency of up to 38%. These are not technologies that are applied in most vehicles.)

You might be interested in
Steam at 75 kPa and 8 percent quality is contained in a spring-loaded piston–cylinder device, as shown in Figure, with an initia
Rashid [163]

The heat transferred to and the work produced by the steam during this process  is 13781.618 kJ/kg

<h3>​How to calcultae the heat?</h3>

The Net Change in Enthalpy will be:

= m ( h2 - h1 ) = 11.216 ( 1755.405 - 566.78 ) = 13331.618 kJ/kg

Work Done (Area Under PV curve) = 1/2 x (P1 + P2) x ( V1 - V2)

= 1/2 x ( 75 + 225) x (5 - 2)

W = 450 KJ

From the First Law of Thermodynamics, Q = U + W

So, Heat Transfer = Change in Internal Energy + Work Done

= 13331.618 + 450

Q = 13781.618 kJ/kg

Learn more about heat on:

brainly.com/question/13439286

#SP1

6 0
2 years ago
Refrigerant-134a at 400 psia has a specific volume of 0.1144 ft3/lbm. Determine the temperature of the refrigerant based on (a)
vekshin1

Answer:

a) Using Ideal gas Equation, T = 434.98°R = 435°R

b) Using Van Der Waal's Equation, T = 637.32°R = 637°R

c) T obtained from the refrigerant tables at P = 400 psia and v = 0.1144 ft³/lbm is T = 559.67°R = 560°R

Explanation:

a) Ideal gas Equation

PV = mRT

T = PV/mR

P = pressure = 400 psia

V/m = specific volume = 0.1144 ft³/lbm

R = gas constant = 0.1052 psia.ft³/lbm.°R

T = 400 × 0.1144/0.1052 = 434.98 °R

b) Van Der Waal's Equation

T = (1/R) (P + (a/v²)) (v - b)

a = Van Der Waal's constant = (27R²(T꜀ᵣ)²)/(64P꜀ᵣ)

R = 0.1052 psia.ft³/lbm.°R

T꜀ᵣ = critical temperature for refrigerant-134a (from the refrigerant tables) = 673.6°R

P꜀ᵣ = critical pressure for refrigerant-134a (from the refrigerant tables) = 588.7 psia

a = (27 × 0.1052² × 673.6²)/(64 × 588.7)

a = 3.596 ft⁶.psia/lbm²

b = (RT꜀ᵣ)/8P꜀ᵣ

b = (0.1052 × 673.6)/(8 × 588.7) = 0.01504 ft³/lbm

T = (1/0.1052) (400 + (3.596/0.1144²) (0.1144 - 0.01504) = 637.32°R

c) The temperature for the refrigerant-134a as obtained from the refrigerant tables at P = 400 psia and v = 0.1144 ft³/lbm is

T = 100°F = 559.67°R

7 0
3 years ago
Multiple Choice
Ymorist [56]

Answer:

Sealing agent

Explanation:

Generally, when we have water leaks in almost any building or equipment, we use a sealant. However, this sealant could be of different types depending on the peculiarity of the leakage.

Thus, the correct answer is sealing agent.

5 0
3 years ago
Read 2 more answers
Select the best answer for the question.
dalvyx [7]
I think the Acid level
5 0
4 years ago
Help i need to find out how to replace a water hose in a truck
Arisa [49]
How long is the old hose
7 0
2 years ago
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