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Crank
3 years ago
14

Which of the following are rights that workers have under OSHA

Engineering
2 answers:
galben [10]3 years ago
7 0

Answer:

hi your question is incomplete the options are lacking so i will list out some rights of workers under OSHA :

  • Right to safe and healthy workplace
  • Right to know about dangerous substances at workplace
  • Right to complain about presence of hazards at workplace

Explanation:

Workers safety and overall well being at work is the primary responsibility of the employer and the right of the employee under the OSHA rules.

The right to safe and healthy workplace: this right is part of the rights been assigned to workers by the OSHA rules. the employer will provide have to a safe working place by removing every hazard in the workplace and in the case were these hazards can't be removed a proper training and protection equipment is provided for the workers to be safe.

Right to know about dangerous substances at workplace : It is the main responsibility of the employer to ensure that every dangerous chemical at work is properly labelled so that the workers will be informed about any potential threat the substances may carry.

right to complain about the presence of hazard at workplace. If there is a potential hazardous equipment or substance discovered on site while at work, it is the responsibility/right of the workers to lay a complain to the authorities about it.

soldi70 [24.7K]3 years ago
5 0

Answer: Employees have the right to file a complaint against their employer without having to fear reprisal from their employer's.

Hope this helps!  :)

Explanation:

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Answer:

yes it is possible

Explanation:

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edge dislocation is a defect where an extra half plane is inside the lattice.

and screw dislocation is one in which can be assumed as the first half of the crystal slips over another.

These dislocation can coexist together where the line direction and burger vectors are  neither parallel nor perpendicular then at that condition both dislocation screw and edge will coexist

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the hoop is cast on the rough surface such that it has an angular velocity w=4rad/s and an angular acceleration a=5rad/s^2. also
IgorLugansk [536]

Given Information:

Angular velocity = ω = 4 rad/s

Angular acceleration = α = 5 rad/s²

Center deceleration = a₀ = 2 m/s

Required Information:

Acceleration of point A at this instant = ?

Answer:

Acceleration of point A at this instant = 5.94 m/s²

Explanation:

Refer to the attached diagram of the question,

The acceleration of point A is given by

a = a₀ + rα - rω²

Where r is the radial distance between the center and point A, a₀ is the deceleration of center, α is the angular acceleration and ω is the angular velocity.

a = -2i + 0.3j*5k - 0.3j*4²

a = -2i + 1.5(j*k) - 0.3j*16

a = -2i + 1.5(-i) - 4.8j

a = -2i - 1.5i - 4.8j

a = -3.5i - 4.8j

The magnitude of acceleration vector is

a = √(-3.5)² + (-4.8)²

a = √35.29

a = 5.94 m/s²

Therefore, the acceleration of point A is 5.94 m/s²

The angle is given by

θ = tan⁻¹(y/x)

θ = tan⁻¹(-4.8/-3.5)

θ = 53.9°

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