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4 years ago

I’ll cash app 20 and 50 points text me after you answer.

Mathematics

2 answers:

mestny [16]4 years ago

7 0

Answer:

Negative Feedback Control of the Amplifier is achieved by applying a small part of the output voltage signal at Vout back to inverting (-) input terminal via the feedback resistor, RF

bogdanovich [222]4 years ago

6 0

What is a negative feedback control?

A negative feedback control is part of the amplifier. This can be gained by taking a small part of voltage and putting it back to upend input terminal. This can be located in the feedback resistor.

Why is it used?

The feedback part reduces the gain in the system. The degree of reduction is similar to the open loop the system contains. Negative feedback reduces things like...

Sensitivity
Distortion
Noise

...to improve the overall system bandwidth and impedance from both the input and output.

Best of Luck!

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3 years ago

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Jordan estimated that his paper airplane would fly 42 feet. It actually traveled 50 feet. What was the percent error?

topjm [15]

$\huge \mathcal{ Answer࿐}$

Error (e) = 50 - 42 = 8 feet

assumed value (a) = 42 feet

$\boxed{ \mathrm{ \% \: error = \dfrac{error}{assumed \: value} \times 100}}$

$\mathrm{ \% \: error =\dfrac{8}{42}} \times 100$

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6 0

3 years ago

Find y Round to the nearest tenth: 28° X 350 ft y y = [ ? ]ft Enter

NeTakaya

Answer:

y = 658.3 ft

Step-by-step explanation:

Angle of depression = angle of elevation = 28° (alternate angles are congruent)

Reference angle = 28°

Side length opposite to reference angle = 350 ft

Adjacent = y

Apply trigonometric function, TOA:

Tan 28 = Opp/Adj

Tan 28 = 350/y

y*Tan 28 = 350

y = 350/Tan 28

y = 658.254263 ≈ 658.3 ft (nearest tenth)

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3 years ago

What is the slope of the line?

Vikki [24]

Answer:

Step-by-step explanation:

from (0,1) to (1,3)

is up 2 over 1

2/1=2

hope this helps!

3 0

3 years ago

A lamp has two bulbs, each of a type with average lifetime 1400 hours. Assuming that we can model the probability of failure of

liq [111]

Answer:

The probability of failure of both the bulbs is 0.4323.

Step-by-step explanation:

For an exponential distribution the distribution is given by

$f(x,\lambda )=\int_{0}^{x }\lambda e^{-\lambda x}dx$

The value of λ is related to the mean μ as λ=1/μ,

Let us denote the 2 bulbs by X and Y thus the probability distribution of the 2 bulbs is as under

$P(X)=\int_{0}^{x }\lambda _{X}e^{-\lambda _{X}x}dx$

Similarly for the bulb Y the distribution function is given by

$P(Y)=\int_{0}^{y }\lambda _{Y}e^{-\lambda _{Y}y}dy$

Thus the probability for both the bulbs to fail within 1500 hours is

$P(E)=\int_{0}^{1500}\int_{0}^{1500}\frac{1}{1400}e^{\frac{-x}{1400}}\cdot \frac{1}{1400}e^{\frac{-y}{1400}}dxdy\\\\P(E)=\frac{1}{1400^2}(\int_{0}^{1500}\int_{0}^{1500}e^{\frac{-x}{1400}}\cdot e^{\frac{-y}{1400}}dxdy)\\\\P(E)=\frac{1}{1400^2}(\int_{0}^{1500}e^{\frac{-x}{1400}}dx)\cdot (\int_{0}^{1500}e^{\frac{-y}{1400}}dy)\\\\P(E)=\frac{1}{1400^{2}}\times 920.473\times 920.473\\\\\therefore P(E)=0.4323$

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3 years ago