Answer:
10.00 mL
Explanation:
Please, do not forget to write the dot and 2 of Zeros after the number 10 in the answer!
Please see the step-by-step solution in the picture attached below.
Hope this answer can help you. Have a nice day!
Answer:
The answer to your question is pH = 2.2
Explanation:
Data
pH = ?
moles of HCl = 0.927
volume = 150 l
Process
1.- Calculate the Molar concentration of HCl
Molarity = moles / volume (L)
Molarity = 0.927 / 150
= 0.00618
2.- Calculate the pH
pH = -log [HCl]
Substitution
pH = -log [0.00618]
Result
pH = 2.2
Answer:
0.74 grams of methane
Explanation:
The balanced equation of the combustion reaction of methane with oxygen is:
it is clear that 1 mol of CH₄ reacts with 2 mol of O₂.
firstly, we need to calculate the number of moles of both
for CH₄:
number of moles = mass / molar mass = (3.00 g) / (16.00 g/mol) = 0.1875 mol.
for O₂:
number of moles = mass / molar mass = (9.00 g) / (32.00 g/mol) = 0.2812 mol.
- it is clear that O₂ is the limiting reactant and methane will leftover.
using cross multiplication
1 mol of CH₄ needs → 2 mol of O₂
??? mol of CH₄ needs → 0.2812 mol of O₂
∴ the number of mol of CH₄ needed = (0.2812 * 1) / 2 = 0.1406 mol
so 0.14 mol will react and the remaining CH₄
mol of CH₄ left over = 0.1875 -0.1406 = 0.0469 mol
now we convert moles into grams
mass of CH₄ left over = no. of mol of CH₄ left over * molar mass
= 0.0469 mol * 16 g/mol = 0.7504 g
So, the right choice is 0.74 grams of methane
