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konstantin123 [22]
3 years ago
5

20 moles of NH3 are needed to produce ? Moles of H2O

Chemistry
1 answer:
AfilCa [17]3 years ago
5 0

Hi :)

20 mol NH3 x 6 H2O/4 NH3 = 30 mol H2O

Hope this helped :)

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How many electrons does the nickel ion contain in the compound NiS?
Nostrana [21]

There are 26 electrons in the nickel ion in the compound NiS.

<h3>How many electrons does the nickel ion contain in the compound NiS?</h3>

The number of electrons in a neutral Nickel atom is obtained from the atomic number of Nickel.

The atomic number of Nickel is 28, therefore, the neutral nickel atom has 28 electrons.

In  the compound NiS, nickel atom loses two electrons to to form the nickel ion.

Number of electrons left = 28 - 2 = 26

Therefore, there are 26 electrons in the nickel ion in the compound NiS.

In conclusion, nickel atom loses two electrons to form nickel ion in NiS.

Learn more about electrons at: brainly.com/question/860094

#SPJ1

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1 year ago
Noble gas notation write the electron configuration for the manganese atom
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<span> the electron configuration for the manganese atom [Ne]3s</span>²
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Hii can someone help me pls this is the last question
lara31 [8.8K]

Answer:

B. 126

Explanation:

the scale is 1 to 42 so the scale would be:

3 cm:x cm

3 * 42 = 126 cm

8 0
2 years ago
Any help would be appreciated. Confused.
masya89 [10]

Answer:

q(problem 1) = 25,050 joules;  q(problem 2) = 4.52 x 10⁶ joules

Explanation:

To understand these type problems one needs to go through a simple set of calculations relating to the 'HEATING CURVE OF WATER'. That is, consider the following problem ...

=> Calculate the total amount of heat needed to convert 10g ice at -10°C to steam at 110°C. Given are the following constants:

Heat of fusion (ΔHₓ) = 80 cal/gram

Heat of vaporization (ΔHv) = 540 cal/gram

specific heat of ice [c(i)] = 0.50 cal/gram·°C

specific heat of water [c(w)] = 1.00 cal/gram·°C

specific heat of steam [c(s)] = 0.48 cal/gram·°C

Now, the problem calculates the heat flow in each of five (5) phase transition regions based on the heating curve of water (see attached graph below this post) ...   Note two types of regions (1) regions of increasing slopes use q = mcΔT and (2) regions of zero slopes use q = m·ΔH.

q(warming ice) =  m·c(i)·ΔT = (10g)(0.50 cal/g°C)(10°C) = 50 cal

q(melting) = m·ΔHₓ = (10g)(80cal/g) 800 cal

q(warming water) = m·c(w)·ΔT = (10g)(1.00 cal/g°C)(100°C) = 1000 cal

q(evaporation of water) =  m·ΔHv = (10g)(540cal/g) = 5400 cal

q(heating steam) = m·c(s)·ΔT = (10g)(0.48 cal/g°C)(10°C) = 48 cal

Q(total) = ∑q = (50 + 800 + 1000 + 5400 + 48) = 7298 cals. => to convert to joules, multiply by 4.184 j/cal => q = 7298 cals x 4.184 j/cal = 30,534 joules = 30.5 Kj.

Now, for the problems in your post ... they represent fragments of the above problem. All you need to do is decide if the problem contains a temperature change (use q = m·c·ΔT) or does NOT contain a temperature change (use q = m·ΔH).    

Problem 1: Given Heat of Fusion of Water = 334 j/g, determine heat needed to melt 75g ice.

Since this is a phase transition (melting), NO temperature change occurs; use q = m·ΔHₓ = (75g)(334 j/g) = 25,050 joules.

Problem 2: Given Heat of Vaporization = 2260 j/g; determine the amount of heat needed to boil to vapor 2 Liters water ( = 2000 grams water ).

Since this is a phase transition (boiling = evaporation), NO temperature change occurs; use q = m·ΔHf = (2000g)(2260 j/g) = 4,520,000 joules = 4.52 x 10⁶ joules.

Problems containing a temperature change:

NOTE: A specific temperature change will be evident in the context of problems containing temperature change => use q = m·c·ΔT. Such is associated with the increasing slope regions of the heating curve.  Good luck on your efforts. Doc :-)

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3 years ago
What do all four animals have in common? cat worm spider crab
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<span>They are composed of cells</span>
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