Molarity = 3.9 * 10 ^ -8
pH = - log (3.9 * 10 ^ -8)
pH = - (-7.40893539)
pH = 7.409 = 7.4 ... Ans
Answer:
Explanation:
At constant pressure and temperature, the mole ratio of the gases is equal to their volume ratio (a consequence of Avogadro's law).
Hence, the <em>complete combustion reaction</em> that has a ratio of 100 ml of gaseous hydrocarbon to 300 ml of oxygen, is that whose mole ratio is 1 mol hydrocarbon : 3 mol of oxygen.
Then, you must write the balanced chemical equations for the complete combustion of the four hydrocarbons in the list of choices, and conclude which has such mole ratio (1 mol hydrocarbon : 3 mol oxygen).
A complete combustion reaction of a hydrocarbon is the reaction with oxygen that produces CO₂ and H₂O, along with the release of heat and light.
<u>a. C₂H₄:</u>
- C₂H₄ (g) + 3O₂ (g) → 2CO₂(g) + 2H₂O (g)
Precisely, for this reaction the mole ratio is 1 mol C₂H₄: 2 mol O₂, hence, this is the right choice.
The following analysis just shows that the other options are not right.
<u>b. C₂H₂:</u>
- 2C₂H₂ (g) + 5O₂ (g) → 4CO₂(g) + 2H₂O (g)
The mole ratio for this reaction is 2 mol C₂H₂ :5 mol O₂.
<u>с. С₃Н₈</u>
- C₃H₈ (g) + 5O₂ (g) → 3CO₂(g) + 4H₂O (g)
The mole ratio is 1 mol C₃H₈ : 5 mol O₂
<u>d. C₂H₆</u>
- 2C₂H₆ (g) +7 O₂ (g) → 4CO₂(g) + 6H₂O (g)
The mole ratio is 2 mol C₂H₆ : 7 mol O₂
Answer:
so far from what i've seen its been 80 mil
Explanation:
the power of GoogIe
Answer:

Explanation:
First write the balance eqation of chemical reaction:

Remember writing any chemical reaction from its elemetal form then write the elements in their natural form i.e. how that element exists in the nature here sulphur exists in solid monoatomic form in the nature and oxygen in gaseous diatomic form.
mass of oxygen given=5gram
mole of oxygen
mass of sulpher given=6gram
mole of sulpher
from the above balanced equaion;
2 mole of sulphur reacts with 3 mole Oxygen completely
1 mole of sulphur reacts with 1.5 mole Oxygen completely
0.19 mole of sulphur reacts with
i.e. 0.285 mole Oxygen completely.
but we have 0.16 mole so oxygen will be the limiting reagent and sulpher will be the excess reagent
so product will depend on the limiting reagent
from the balance equation
3 mole of sulpher gives 2 mole 
1 mole of sulpher will give 2/3 mole 
0.16 of sulpher will give 0.12 mole 
mass of
=9.6gram this is theoreical production of
and
actual production of
=7.9gram



The formula we can use here is the Plancks equation:
E = h c / ʎ
where h is Plancks constant = 6.626 × 10-34 m2 kg / s, c
is speed of light = 3 x 10^8 m/s and ʎ is wavelength = 656.1 x 10^-9 m
Therefore E is:
E = (6.626 × 10-34 m2 kg / s)
* (3 x 10^8 m/s) / 656.1 x 10^-9 m
<span>E = 3.03 x 10^-19 J</span>