Answer:
0.699 L of the fluid will overflow
Explanation:
We know that the change in volume ΔV = V₀β(T₂ - T₁) where V₀ = volume of radiator = 21.1 L, β = coefficient of volume expansion of fluid = 400 × 10⁻⁶/°C
and T₁ = initial temperature of radiator = 12.2°C and T₂ = final temperature of radiator = 95.0°C
Substituting these values into the equation, we have
ΔV = V₀β(T₂ - T₁)
= 21.1 L × 400 × 10⁻⁶/°C × (95.0°C - 12.2°C)
= 21.1 L × 400 × 10⁻⁶/°C × 82.8°C = 698832 × 10⁻⁶ L
= 0.698832 L
≅ 0.699 L = 0.7 L to the nearest tenth litre
So, 0.699 L of the fluid will overflow
It must be sliding friction, because the fish is already in motion.
Answer:
The magnitude of the tension in the cable, T is 1,064.315 N
Explanation:
Here we have
Length of beam = 4.0 m
Weight = 200 N
Center of mass of uniform beam = mid-span = 2.0 m
Point of attachment of cable = Beam end = 4.0 m
Angle of cable = 53° with the horizontal
Tension in cable = T
Point at which person stands = 1.50 m from wall
Weight of person = 350 N
Therefore,
Taking moment about the wall, we have
∑Clockwise moments = ∑Anticlockwise moments
T×sin(53) = 350×1.5 + 200×2
T = 850/sin(53) = 1,064.315 N.
Answer:
I took 3*sqrt(10/83)= 1.110349815
And rounded to 1.11 Hz
Explanation:
Answer:
The pressure at point 2 is 
Explanation:
From the question we are told that
The speed at point 1 is 
The gauge pressure at point 1 is 
The density of water is 
Let the height at point 1 be 
then the height at point two will be
Let the diameter at point 1 be 
then the diameter at point two will be
Now the continuity equation is mathematically represented as
Here 
are the area at point 1 and 2
Now given that the are is directly proportional to the square of the diameter [i.e 
]
which can represent as
=> 
where c is a constant
so 
=> 
=> 
Now from the continuity equation
=> 
=> 
Generally the Bernoulli equation is mathematically represented as
So
=> 
substituting values
