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stiv31 [10]
2 years ago
12

Which of the following is not true of a conductor? A. It is used in electrical circuits. B. It allows easy passage of moving cha

rge. C. It is frequently made of glass or rubber. D. It is often made of metals like copper or iron.
Physics
2 answers:
Oksi-84 [34.3K]2 years ago
8 0
Three of the statements are true.  'D' is false.
Glass and rubber are excellent insulators, total duds as conductors.
yuradex [85]2 years ago
8 0

Answer:

Explanation:

glass or rubber apex ;)

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If a car has an initial velocity of 20 m/s and accelerates at 2.0 m/s2 for 100 m, what is its final velocity?
rodikova [14]

Answer:

28.28 ms-1

Explanation:

v² = u² + 2as

v² = 20² + 2×2×100

v²= 800

v = 28.28 ms-1

3 0
3 years ago
A bus covers 10 km in 7 minutes. Find the speed of the bus in km/h
Shtirlitz [24]

Answer:

Explanation: so how many minutes are in an hour 60 right, and the bus travels 10km in 7 minutes right so use math the bus travels 14km in 10 minutes so the bus travels 98km in an hour

8 0
3 years ago
Swinging a tennis racket against a ball is an example of a third class lever. Please select the best answer from the choices pro
kari74 [83]
that statement is true

a Third class lever applied when the effort place between the load and the fulcrum.

For example, in a forearm serve
Fulcrum : The elbow
Effort : The effort that putted by the biceps muscle
Load : The arm

7 0
3 years ago
Read 2 more answers
Charge is uniformly distributed around a ring of radius R and the resulting electric field magnitude E is measured along the rin
Arte-miy333 [17]

Answer:

x=\dfrac{r}{\sqrt2}

Explanation:

Given that

Radius =r

Electric filed =E

Q=Charge on the ring

The electric filed at distance x given as

E=K\dfrac{Q}{(r^2+x^2)^{3/2}}

For maximum condition

\dfrac{dE}{dx}=0

E=K{Q}{(r^2+x^2)^{-3/2}}

\dfrac{dE}{dx}=K{Q}{(r^2+x^2)^{-3/2}}-\dfrac{3}{2}\times 2\times x\times K{Q}{(r^2+x^2)^{-5/2}}

For maximum condition

\dfrac{dE}{dx}=0

K{Q}{(r^2+x^2)^{-3/2}}-\dfrac{3}{2}\times 2\times x\times K{Q}{(r^2+x^2)^{-5/2}}=0

r^2+x^2-3x^2=0

x=\dfrac{r}{\sqrt2}

At x=\dfrac{r}{\sqrt2} the electric field will be maximum.

3 0
2 years ago
IM SOO CONFUSED PLS HELP!! The mass of the nucleus is approximately EQUAL to the mass number multiplied by ____ Atomic Mass unit
nevsk [136]

Answer:

option a.

Explanation:

We can think of an atom as a nucleus (where the protons and neutrons are) and some electrons orbiting it.

We also know that the mass of an electron is a lot smaller than the mass of a proton or the mass of an electron.

So, if all the protons and electrons of an atom are in the nucleus, we know that most of the mass of an atom is in the nucleus of that atom.

Then we define the mass number, which is the total number of protons and neutrons in an atom. Such that the mass of a proton (or a neutron) is almost equal to 1u

Then if we define A as the total number of protons and neutrons, and each one of these weights about 1u

(where u = atomic mass unit)

Then the weight of the nucleus is about A times 1u, or:

A*1u = A atomic mass units.

Then the correct option is:

The mass of the nucleus is approximately EQUAL to the mass number multiplied by __1__ Atomic Mass unit.

option a.

5 0
3 years ago
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