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sukhopar [10]
3 years ago
14

A container has the dimensions of 10 cm x 50 mm x 0.2 m. It is filled completely with 5.0 kg of a powdery ore. What is the densi

ty of the ore in g/cm3 ? (D=m/V)
0.05 g/cm3

5.0 g/cm3

50 g/cm3

500 g/cm3
Chemistry
1 answer:
SVETLANKA909090 [29]3 years ago
6 0

Answer:

B

Explanation:

5 kg = 5 kg * 1000 grams / kg = 5000 grams

10 cm does not require any conversion.

50 mm = 50 mm * 1 cm/10 mm = 5 cm

0.2 m = 0.2 m * 100 cm / 1 m = 20 cm

V = 10 cm * 5 cm * 20 cm

V = 1000 cm^3

Density = 5000 grams / 1000 cm^3 = 5 grams / cm^3

B

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A methanol-water mixture is to be flash distilled at 1 atm. If the feed is 25 mole %methanol, what are the liquid and vapor comp
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Answer:

Explanation:

Given that:

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Fz = Lx + Vy

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F = amount of feed

z = mole fraction of ethanol (in feed)

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x = mole fraction of methanol out of the liquid

y  = mole fraction of methanol out of the vapor.

SO;

(a)

If all the feed is vaporized, then the vapor will likely have the same composition as the feed.

(b)

If no vaporization of the feed takes place, then the bottoms moving out of the column contains the same composition as the feed.

(c)

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Fz = (\dfrac{2}{3}F) x + (\dfrac{1}{3}F)y \\ \\ z = \dfrac{2}{3}x+\dfrac{1}{3}y

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0.25 = \dfrac{2}{3}x+\dfrac{1}{3}y

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If 2/3 of the feed is vaporized;

Then:

Fz = (\dfrac{1}{3}F) x + (\dfrac{2}{3}F)y \\ \\ z = \dfrac{1}{3}x+\dfrac{2}{3}y

replacing z = 0.25

0.25 = \dfrac{1}{3}x+\dfrac{2}{3}y

0.75 = x + 2y

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