Answer:
Oxygen is a simple molecular structure, where individual oxygen atoms are bonded to each other by strong covalent bonds. Hence, a low amount of energy is required to overcome these weak forces and oxygen has a low boiling point. Therefore, at room temperature, oxygen is a gas. Oxygen difluoride is a colorless gas, condensable to a pale yellow liquid, with a slightly irritating odor. It is the most stable of the compounds of fluorine and oxygen, which include O,F,, O,F, and 0,F2 but nevertheless it is a strong oxidizing and fluorinating agent. Oxygen Difluoride is a colorless gas or a yellowish-brown liquid with a foul odor. Just to finally link Joseph's answer to the question, oxygen difluoride will thus change from liquid to solid state when chilled from -220°c to -230°c. The boiling point of oxygen is -182.96 degrees Celsius (under 1 standard atmosphere). This means at temperatures below that point, oxygen is a solid or a liquid, and at temperatures above that point, oxygen is a gas. So at -183 degrees Celsius, oxygen is a liquid.
Explanation:
Answer:
Answer: (1R,2S) / (1S, 2R) , (1R,2R) / (1S, 2S)
Explanation:
Sodium borohydride reduction of benzoin will give four possible stereo isomers out of which are (1R,2S) - (1S, 2R) isomers and (1R,2R) - (1S, 2S) isomers which are known as enantiomers.
In general enantiomers show single spot in the TLC as they do not show any difference in Rf value (i.e) (1R,2S) - (1S, 2R) isomers show only one spot although they are two compounds and also (1R,2R) - (1S, 2S) isomers also show one spot. That is the reason why you are observing two spots in the TLC ( of reaction mixture) other than starting materilal.
Explanation:
An ionic equation will be the one in which all the participating species will be present as ions.
The given reaction will be as follows.
Balancing this equation by multiplying 
by 2 and 
by 3 on reactant side. Whereas multiply KBr by 6 on product side.
Hence, the net ionic equation will be as follows.
As both 
and 
are spectator ions. Hence, the net ionic equation will be as follows.
Explain, in terms
of both atoms and molecular structure, why there is no isomer of CH3OH.
There is no isomer of CH3OH or methanol because it
contains only one carbon atom. And also, the structure is tetrahedral, having
four substances attached to the carbon atom.
Answer:
this is not and reaction of acid and base.(CaOCL2)
Explanation:
Ca2, Cl, are base and O is a neutral.
so how can that be a acid and base reaction
