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Natalija [7]
3 years ago
10

Help me with this question!!

Chemistry
1 answer:
skelet666 [1.2K]3 years ago
8 0
Nitrogen is ...19.7
flourine is 80.3...
hope this helps!
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Nikolas, the fire extinguisher, and the skateboard have a combined mass of 50 kg. What force would the fire extinguisher have to
murzikaleks [220]

Answer:

Force used by fire extinguisher = 60 N

Explanation:

Given:

Mass of skateboard with fire extinguisher = 50 kg

Acceleration of fire extinguisher = 1.2 m/s²

Find:

Force used by fire extinguisher = ?

Computation:

⇒ Force = Mass × Acceleration

⇒ Force used by fire extinguisher = Mass of skateboard with fire extinguisher × Acceleration of fire extinguisher

⇒ Force used by fire extinguisher = 50 kg × 1.2 m/s²

⇒ Force used by fire extinguisher = 60 N

3 0
3 years ago
Read 2 more answers
What would be the volume in millilitres of a blood sample of 2.15 microliters (ul)?​
Zanzabum

2.15 x 10⁻³mL

Explanation:

Given parameter:

    Volume of blood sample in uL = 2.15uL

Conversion           uL → mL

   micro- and milli-  are both prefixes of sub-units.

liter is a unit of volume of a substance.

       micro - is 10⁻⁶

       milli- is of the order 10⁻³

The problem is converting from micro to milli:

     if we multiply  10⁻⁶ by 10³ we would have our milli;

  1000uL = 1mL

  2.15uL :   2.15uL x \frac{1mL}{1000uL} = 2.15 x 10⁻³mL

learn more:

Volume brainly.com/question/5055270

#learnwithBrainly

4 0
3 years ago
A solution of 2-propanol and 1-octanol behaves ideally. Calculate the chemical potential of 2-propanol in solution relative to t
andrew-mc [135]

Answer:

The chemical potential of 2-propanol in solution relative to that of pure 2-propanol is lower by 2.63x10⁻³.    

Explanation:

The chemical potential of 2-propanol in solution relative to that of pure 2-propanol can be calculated using the following equation:

\mu (l) = \mu ^{\circ} (l) + R*T*ln(x)

<u>Where:</u>

<em>μ (l): is the chemical potential of 2-propanol in solution    </em>

<em>μ° (l): is the chemical potential of pure 2-propanol   </em>

<em>R: is the gas constant = 8.314 J K⁻¹ mol⁻¹ </em>

<em>T: is the temperature = 82.3 °C = 355.3 K </em>

<em>x: is the mole fraction of 2-propanol = 0.41 </em>

\mu (l) = \mu ^{\circ} (l) + 8.314 \frac{J}{K*mol}*355.3 K*ln(0.41)

\mu (l) = \mu ^{\circ} (l) - 2.63 \cdot 10^{3} J*mol^{-1}

\mu (l) - \mu ^{\circ} (l) = - 2.63 \cdot 10^{3} J*mol^{-1}  

Therefore, the chemical potential of 2-propanol in solution relative to that of pure 2-propanol is lower by 2.63x10⁻³.    

I hope it helps you!    

8 0
3 years ago
Identify the f-block element.
GaryK [48]

Answer: E. none of these

Explanation: because the f-block element is n-2

3 0
3 years ago
Oxygen in the air can react with wood when a match is burned. Ash is produced.
Hitman42 [59]

Answer:

D. Ash is a different substance than wood.

8 0
2 years ago
Read 2 more answers
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