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lubasha [3.4K]
3 years ago
14

Create a string called alphabet containing 'abcdefghijklmnopqrstuvwxyz', then perform the following separate slice operations to

obtain: The first half of the string using starting and ending indices. The first half of the string using only the ending index. The second half of the string using starting and ending indices. The second half of the string using only the starting index. Every second letter in the string starting with 'a'. The entire string in reverse. Every third letter of the string in reverse starting with 'z'.
Computers and Technology
1 answer:
spin [16.1K]3 years ago
7 0

Answer:

There is no short answer.

Explanation:

First let's create the string:

  • alphabetString = "abcdefghijklmnopqrstuvwxyz";

The first half of the string using slice method can be written as:

  • alphabetString.slice(0, 13);

The first half of the string using only the ending index can be written as:

  • alphabetString.slice(-13);

When we put - at the start of the index number, the counting begins at the last element with -1 and goes backwards.

The second half of the string can be written as:

  • alphabetString.slice(13,26);

The second half of the string using only the starting index can be written as:

  • alphabetString.slice(13);

To get the every second letter in the string, we need a for loop:

  • for( let x = 0; x < alphabetString.length(); x = x + 2){

                 alphabetString.slice(x);

}

To get the entire string in reverse, we can use the reverse method that is built-in:

  • alphabetString.reverse();

To get the every third letter of the string, we can again use a for loop:

  • for( let x = -1; x = -27; x = x - 3){

                  alphabetString.slice(x);

}

I hope this answer helps.

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Description:
Nastasia [14]

Answer:

The programming language is not stated (I'll answer using C++)

#include <iostream>

using namespace std;

int convert(float miles)

{

   return miles * 5280;

}

int main() {

   cout<<"Console:"<<endl;

   cout<<"Hike Calculator"<<endl;

   float miles;

   char response;

   cout<<"How many miles did you walk?. ";

   cin>>miles;

   cout<<"You walked "<<convert(miles)<<" feet"<<endl;

   cout<<"Continue? (y/n): ";

   cin>>response;

   while(response == 'y')

   {

   cout<<"How many miles did you walk?. ";

   cin>>miles;

   cout<<"You walked "<<convert(miles)<<" feet"<<endl;

   cout<<"Continue? (y/n): ";

   cin>>response;

   }

   cout<<"Bye!";

   return 0;

}

Explanation:

Here, I'll explain some difficult lines (one after the other)

The italicized represents the function that returns the number of feet

<em>int convert(float miles) </em>

<em>{ </em>

<em>    return miles * 5280; </em>

<em>} </em>

The main method starts here

int main() {

The next two lines gives an info about the program

   cout<<"Console:"<<endl;

   cout<<"Hike Calculator"<<endl;

   float miles;

   char response;

This line prompts user for number of miles

   cout<<"How many miles did you walk?. ";

   cin>>miles;

This line calls the function that converts miles to feet and prints the feet equivalent of miles

   cout<<"You walked "<<convert(miles)<<" feet"<<endl;

This line prompts user for another conversion

   cout<<"Continue? (y/n): ";

   cin>>response;

This is an iteration that repeats its execution as long as user continue input y as response

<em>    while(response == 'y') </em>

<em>    { </em>

<em>    cout<<"How many miles did you walk?. "; </em>

<em>    cin>>miles; </em>

<em>    cout<<"You walked "<<convert(miles)<<" feet"<<endl; </em>

<em>    cout<<"Continue? (y/n): "; </em>

<em>    cin>>response; </em>

<em>    } </em>

   cout<<"Bye!";

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