Alright, so plugging it in, we get 2(-4)^2=2(2)^4+3^2-(-4)^2+2^4. Use PEMDAS with parenthesis and exponents to then get (2)(16)+9-16+16. Multiplying 1 and 16, we get 32+41-16+16=73
Part A.
You need two equations with the same slope and different y-intercepts.
Their graph is parallel lines. Since the lines do not intersect, there is no solution.
y = 2x + 2
y = 2x - 2
Part B.
We use the first equation as above. For the second equation, we use an equation with different slope. Two lines with different slopes always intersect.
y = 2x + 2
y = -2x - 2
In the second equation, y = -2x - 2. We now substitute -2x - 2 for y in the first equation.
-2x - 2 = 2x + 2
-4x = 4
x = -1
Now substitute -1 for x in the first equation to find y.
y = 2x + 2
y = 2(-1) + 2
y = -2 + 2
y = 0
Solution: x = -1 and y = 0
65 Bc absolute value of negative is positive
XZ=XY+YZ
JL=JK+KL
use the trigonometric values table or unit circle to calculate the expression
