Question

Evaluate the trigonometric ratio​

Answer 1

Answer:

1

Step-by-step explanation:

Given $\lim_{x \to 0} \frac{sinxcosx}{x}$

multiply the numerator and denominator with 2

we get $\lim_{x \to 0} \frac{2sinxcosx}{2x}$

We know that sin2x=2sinxcosx

$\lim_{x \to0} \frac{sin2x}{2x}$

Now consider y=2x

As x→0 2x→0 y→0

Now limit changes to

$\lim_{y \to0} \frac{siny}{y}$=1