Answer:
Smax = 676 ft
the maximum altitude (height) the rocket will attain during its flight is 676 ft
Step-by-step explanation:
Given;
The height function S(t) of the rocket as;
S(t) = -16t2 + 208t
The maximum altitude Smax, will occur at dS/dt = 0
differentiating S(t);
dS/dt = -32t + 208 = 0
-32t +208 = 0
32t = 208
t = 208/32
t = 6.5 seconds.
The maximum altitude Smax is;
Substituting t = 6.5 s
Smax = -16(6.5)^2 + 208(6.5)
Smax = 676 ft
the maximum altitude (height) the rocket will attain during its flight is 676 ft
Answer:
1410ft²
Step-by-step explanation:
20 * 12 * 2 + [62 * (15 + 12)] =
480 + (62 * 15) =
480 + 930 =
1410ft²
Answer:
It's the first one
Step-by-step explanation:
Because 2M means you are multiplying all the values of M with 2
Answer:
k = 11
Step-by-step explanation:
Given the points are collinear then the slopes between consecutive points are equal.
Using the slope formula
m = 
with (x₁, y₁ ) = (5, 1) and (x₂, y₂ ) = (1, - 1)
m = 
= 
= 
Repeat with another 2 points and equate to
with (x₁, y₁ ) = (1, - 1) and (x₂, y₂ ) = (k, 4)
m = 
, then
= ( cross- multiply )
k - 1 = 10 ( add 1 to both sides )
k = 11
