1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lana [24]
3 years ago
11

What is the importance of Scientific Notation and Significant Figures?

Physics
1 answer:
irakobra [83]3 years ago
7 0

Answer:

they're important because they simplify the results of the comparison

You might be interested in
What is the height in meters of a person who is 6 ft 1.0 in. Tall?
Aliun [14]

Answer:1.85 m

Explanation:

3 0
3 years ago
Read 2 more answers
Which is not a principle of fitness?<br> Overload<br> Height<br> Specificity<br> Individuality
Nitella [24]

Answer:

Height

Explanation:

7 0
3 years ago
Read 2 more answers
Two protons (each with q = 1.60 x 10-19)
otez555 [7]

Answer:

230.4 N

Explanation:

From the question given above, the following data were obtained:

Charge (q) of each protons = 1.6×10¯¹⁹ C

Distance apart (r) = 1×10¯¹⁵ m

Force (F) =?

NOTE: Electric constant (K) = 9×10⁹ Nm²/C²

The force exerted can be obtained as follow:

F = Kq₁q₂ / r²

F = 9×10⁹ × (1.6×10¯¹⁹)² / (1×10¯¹⁵)²

F = 9×10⁹ × 2.56×10¯³⁸ / 1×10¯³⁰

F = 2.304×10¯²⁸ / 1×10¯³⁰

F = 230.4 N

Therefore, the force exerted is 230.4 N

5 0
3 years ago
What mass, in grams, of aluminum fins could 2571 J of energy heat from 15.73 ∘C to 26.50 ∘C ? Aluminum has a specific heat of 0.
nadya68 [22]

Answer:

266 g or 0.266 kg

Explanation:

The formula for specific heat capacity is given as,

Q = cm(t₂-t₁) ..................... Equation 1

Where Q = Heat Energy, c = specific heat capacity of Aluminum, m = mass of the aluminum fins, t₁ = initial temperature, t₂ = final temperature.

make m the subject of the equation,

m = Q/c(t₂-t₁)................... Equation 2

Given : Q = 2571 J, c = 0.897 J/g.°C, t₁ = 15.73 °C, t₂ = 26.50 °C.

Substitute into equation 2

m = 2571/[0.897×(26.5-15.73)]

m = 2571/9.661

m = 266 g or 0.266 kg

Hence the mass of the Aluminum fins = 266 g or 0.266 kg

5 0
4 years ago
Suppose a small quantity of radon gas, which has a half-life of 3.8 days, is accidentally released into the air in a laboratory.
Daniel [21]

Answer:

1 day

Explanation:

Let the safe level = x

The current level = x + 0.2x = 1.2 x

Thus,

Half life = 3.8 days

t_{1/2}=\frac {ln\ 2}{k}

Where, k is rate constant

So,  

k=\frac {ln\ 2}{t_{1/2}}

k=\frac {ln\ 2}{3.8}\ days^{-1}

The rate constant, k = 0.1824 days⁻¹

Using integrated rate law for first order kinetics as:

[A_t]=[A_0]e^{-kt}

Where,  

[A_t] is the concentration at time t

[A_0] is the initial concentration

So,

\frac {[A_t]}{[A_0]} = x / 1.2 x = 0.8333

t = ?

\frac {[A_t]}{[A_0]}=e^{-k\times t}

0.8333=e^{-0.1824\times t}

t ≅ 1 day

<u>Lab must be vacated in 1 day.</u>

4 0
3 years ago
Other questions:
  • To have momentum, an object must be ______. A. heavy B. massive C. moving D. accelerating
    5·2 answers
  • A car with a mass of 1.50x10^3 kg starts from rest and accelerates to a speed of 18.0m/s in 12.0 s. assume that the force of res
    10·1 answer
  • Electric power companies measure energy consumption in kilowatt-hours, denoted kWh. One kilowatt-hour is the amount of energy tr
    10·1 answer
  • The bending of light as it passes into a transparent material of different optical intensity is known as
    12·1 answer
  • Help pls it’s urgent
    7·2 answers
  • Which of the following provides evidence that there must be at least two types of electrical charge, but that there is only one
    5·1 answer
  • Help This is Urgent
    5·2 answers
  • The car's initial speed was 32m / s and it takes 99 seconds for the car to come to a full stop after the driver applies the brak
    5·1 answer
  • What is the acceleration of an object with a mass of 367 kg when a net force of 183 N is applied to it
    13·1 answer
  • A steel rod has a radius of 10mm and a
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!