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navik [9.2K]
3 years ago
12

The climber dropped her compass at the end of her 240-meter climb. How long did it take to strike bottom?

Physics
2 answers:
Maru [420]3 years ago
6 0

Answer:

7 seconds

Explanation:

Let's first write down what we have so that we can choose the correct equation of linear motion

initial velocity (u) = 0 m/s

distance (x) = h = 240 m

acceleration (a) = g = 9.81 m/s²

s = ut + \frac{at^{2} }{2} \\\\240 = (0)(t) + \frac{9.81t^{2} }{2}\\ \\9.81t^{2} = 480\\\\t = 6.99s\\\\t = 7 s

ANEK [815]3 years ago
4 0

240 = 0+1/2 (-9.8t

240 = -4.9t

<span>240/-4.9 = t</span><span>
</span>49.0 = t

t= 7.0s

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MrMuchimi
In navigation bearing refers to : 1. the direction of motion itself; 2. the direction of a distant object relative to the current course 3.the angle away from North of a distant point as observed at the current point.

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6 0
3 years ago
One ounce of a well-known breakfast cereal contains 103 Calories (1 food Calorie = 4186 J). If 1.6% of this energy could be conv
faust18 [17]

Answer:

the heaviest barbell that could be lifted  is 390.6kg

Explanation:

Hello!

To solve this question you must follow the following steps

1. Find the amount of energy that can transform the body into motion, this is achieved by multiplying the breakfast consumed by the percentage of energy conversion.

W=(103Calories)(0.016)\frac{4186J}{1calorie} =6898.5J

2. We use the equation that defines the work done by a body that has weight when it is lifted, this is defined by the product of mass by gravity by height.

W=mgh

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m=mass

g=gravity=9.81m/s^2

h=height=1.8m

now we solve for mass, and use the values.

m=\frac{W}{hg} =\frac{6898.5}{(1.8)(9.81)} =390.6kg

the heaviest barbell that could be lifted  is 390.6kg

5 0
2 years ago
Suppose an object is moving 2.1 m/s north on a river, but the river is flowing to the east at a velocity of 1.2 m/s. What is the
rewona [7]

Answer:

2.4 m/s

Explanation:

Given:

Velocity of the object moving north = 2.1 m/s

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Since the directions of velocity of object and river are perpendicular to each other, the magnitude of the resultant velocity is obtained using Pythagoras Theorem.

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8 0
3 years ago
A 37 N block rests on a horizontal surface. The coefficients of static and kinetic friction between the surface and the block ar
Ne4ueva [31]

Answer:

The frictional force acting on the block is 14.8 N.

Explanation:

Given that,

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Using formula of friction force

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Using formula of frictional force

f = \mu N

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6 0
2 years ago
Calculate the acceleration of a bus whose speed changes from 7 m/s to 16 m/s over a period of 5 s.
Bezzdna [24]
Let’s do this together!

Okay so the acceleration formula is vf-vi over time .

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So the time is 5s so 9m/s divided into 5s is 1.8m/s/2

So the answer is 1.8m\s2
7 0
3 years ago
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