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3 years ago

Why does a projectile fired along a horizontal not follow a straight path?

1 answer:

3 0

Answer: A projectile which is fired horizontally is being constantly acted upon by acceleration due to gravity, acting vertically downwards. Hence, it does not follow a straight line path. Also Why a projectile fixed along the horizontal not follow a straight line path? Because the projectile fired horizontally is constantly acts upon by acceleration due to gravity acting vertically downwards.

Explanation:

Hope this helped :)

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An electromagnetic wave is a kind of a wave which,

Harman [31]

Explanation:

Electromagnetic waves are waves that propagate through space while an electric field and a magnetic field interact with each other.

please mark as brainliest plzz

7 0

2 years ago

Read 2 more answers

An unbalanced force gives a 2.00 kg mass an acceleration of 5.00 m/s? What is the force applied to the object?

valentinak56 [21]

Answer:

10N

Explanation:

Equation: ΣF = ma

Fapp = ma

Fapp = (2kg)(5m/s^2) (im guessing you mean 5.00 m/s^2 not m/s)

Fapp = 10*kg*m/s^2

Fapp = 10N

5 0

2 years ago

A sample of 5.6 L of a gas is at a pressure of 1.5 atm. If the volume of the gas is compressed to 4.8 L, what will the new press

Effectus [21]

Answer:

1.75atm

Explanation:

According to Boyle's law, the pressure P of a fixed mass of gas is inversely proportional to it's volume V provided that the temperature remains constant.

$P\alpha \frac{1}{V}\\hence\\PV=constant$

This implies the following;

$P_1V_1=P_2V_2=...=P_nV_n............(1)$ Provided temperature is kept constant.

Given;

$P_1=1.5atm\\V_1=5.6L\\P_2=?\\V_2=4.8L$

From equation (1), we can write;

$P_1V_1=P_2V_2\\hence\\1.5*5.6=P_2*4.8\\\\P_2=\frac{1.5*5.6}{4.8}\\\\P_2=1.75atm$

Since all the units are consistent, there is no need for conversion.

3 0

3 years ago

Read 2 more answers

a package was determined to have a mass of 5.7kilograms. what's the force of gravity acting on the package on earth?(a)37.93N(b)

Nana76 [90]

The force of gravity on earth is 9.807 m/s^2 (or meters per second per second).
To determine the force applied, multiply the mass of the package (5.7 kg) by the force of gravity on Earth (9.807 m/s^2).
5.7 x 9.807 = 55.86 N The answer is D.

Note: the actual force is 55.89 Newtons.

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3 years ago

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Please help if you have the time

Alex777 [14]

We know, length of segment wave is half the wavelength .

Let, wavelength of wave is $\lambda$ .