I hope the wire is not wound too tightly around the bar magnet.
The device will generate electrical energy when the bar magnet
is moving in or out of the coil of wire.
A) The acceleration is due to gravity at any given point if you look at it vertically, so
.
b)
, so
. We use
and then the final speed must be 0 because it stops at the highest point. So
. Solve for
and you get
c)
, and then we plug the values:
and we already have the time from "b)", so
![Y_m_a_x = [(32sin(25))*(32sin(25)/10)] - 5(32sin(25)/10)^2](https://tex.z-dn.net/?f=Y_m_a_x%20%3D%20%5B%2832sin%2825%29%29%2A%2832sin%2825%29%2F10%29%5D%20-%205%2832sin%2825%29%2F10%29%5E2)
; then we just rearrange it
![Y_m_a_x = 10[(32sin(25))^2/100] - 5 [(32sin(25))^2/100]](https://tex.z-dn.net/?f=Y_m_a_x%20%3D%2010%5B%2832sin%2825%29%29%5E2%2F100%5D%20-%205%20%5B%2832sin%2825%29%29%5E2%2F100%5D%20)
and finally
![Y_m_a_x = 5[(32sin(25))^2/100] = (32sin(25))^2/20](https://tex.z-dn.net/?f=Y_m_a_x%20%3D%205%5B%2832sin%2825%29%29%5E2%2F100%5D%20%3D%20%2832sin%2825%29%29%5E2%2F20)
Answer:
d. 3332.5 [N]
Explanation:
To solve this problem we will use newton's second law, which tells us that the sum of forces is equal to the product of mass by acceleration.
Here we have two forces, the force that pushes the car to move forward and the friction force.
The friction force is equal to the product of the normal force by the coefficient of friction.
f = N * μ
f = (m*g) * μ
where:
N = weight of the car = 2150*9.81 = 21091.5 [N]
μ = 0.25
f = (21091.5) * 0.25
f = 5273 [N]
Now as the car is moving forward, the car wheels move clockwise. The friction force between the wheels of the car and the pavement must be counterclockwise, i.e. counterclockwise. Therefore the direction of this force is forward. This way we have:
F + f = m*a
F + 5273 = 2150*4
F = 8600 - 5273
F = 3327 [N]
Therefore the answer is d.
Answer:
Explanation:
g = Acceleration due to gravity = 9.80 m/s²
a = Acceleration= 3.6 m/s²
= Angle = 27°
The equation is
Mass gets cancelled
Rearranging for 
The simplified expression is
*the options are incomplete. The above answer is the required solution
Answer: (c) 2000 N
Explanation:
Given Data :
▪ Initial velocity = zero ( body is at rest)
▪ Distance travelled = 100m
▪ Final kinetic energy = 200000J
To Find :
▪ Resultant force acting on the car.
Therefore:
W = F × d = ΔK ----------------- eq 1.
where,
W = work done
F = applied force
d = distance
ΔK = change in kinetic energy
Calculation :
→ F × d = Kf - Ki ----------------- eq 2.
Where:
Kf = Final kinetic energy = 200000
Ki = initial kinetic energy = 0
Substituting our values into the formula from equation (2)
→ F × 100 = 200000 - 0
→ F = 200000/100
→ F = 2000N
