All categories

3 years ago

What did early experiments and Coulomb’s Law describe? Select all that apply.

2 answers:

4 0

<span>Like charges repel and opposite charges attract.
The further away two charged objects are the weaker the electrical force between them.
The closer two charged objects are the stronger the electrical force between them.
Hope this helps :)</span>

Varvara68 [4.7K]3 years ago

4 0

Answer:

Option (2), (4), (6)

Explanation:

According to the properties of charges, two like charges repel each other and two unlike charges attract each other.

If two positive or two negative charges kept at a distance, then they repel each other.

If one positive and one negative charges kept at a distance, they always attract each other.

Now according to the Coulomb's law, the force between the two charges, is directly proportional to the product of two charges and inversely proportional to the square of distance between them.

So, farther the two charges, weaker is the force.

And closer the two charges, stronger is the force.

You might be interested in

Which is an example of a scientist using a conceptual model to describe a volcano?

Yuri [45]

I would say D would be the answer. but is this even a real like homework question

8 0

3 years ago

Read 2 more answers

In the year 2081 in a shipping port on the moon, workers for Ore-Space, Inc., hoist a 500.0 kg hunk of anorthosite moon rock by

Naddik [55]

Answer:

2,800 n

Explanation:

hope this helps, have a nice day/night! :D

7 0

3 years ago

For a moving object, the force acting on the object varies directly with the object's acceleration. When a force of 81 N acts on

tensa zangetsu [6.8K]

Answer:

18 N

Explanation:

You have to do:

81 N: 9 ms2= x: 2 ms2

6 0

3 years ago

Consider two ideal gases, A & B, at the same temperature. The rms speed of the molecules of gas A is twice that of gas B. Ho

uysha [10]

Answer:

option (d)

Explanation:

The relation between the rms velocity and the molecular mass is given by

v proportional to \frac{1}{\sqrt{M}} keeping the temperature constant

So for two gases

$\frac{v_{A}}{v_{B}}=\sqrt{\frac{M_{B}}{M_{A}}}$

$\frac{2v_{B}}{v_{B}}=\sqrt{\frac{M_{B}}{M_{A}}}$

${\frac{M_{B}}{M_{A}}} = 4$

${\frac{M_{B}}{4}} = M_{A}$

7 0

3 years ago

A 25kg chair initially at rest on a horizontal floor requires a 165 N horizontal force to set it in motion. Once the chair is in

SCORPION-xisa [38]

Answer:

$\mu_k=0.51$

Explanation:

Given that

Mass , m = 25 kg

We know that when body is in rest condition then static friction force act on the body and when body is in motion the kinetic friction force act on the body .That is why these two forces are given as follows

Static friction force ,fs= 165 N

Kinetic friction force ,fk = 127 N

If the body is moving with constant velocity ,it means that acceleration of that body is zero and all the forces are balanced.

Lets take coefficient of kinetic friction = μk

The kinetic friction is given as follows

fk = μk m g

Now by putting the values

127 = μk x 25 x 9.81

$\mu_k=\dfrac{127}{25\times 9.81}$

$\mu_k=0.51$

Therefore the value of coefficient of kinetic friction will be 0.51

4 0

3 years ago