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3 years ago

What did early experiments and Coulomb’s Law describe? Select all that apply.

2 answers:

4 0

<span>Like charges repel and opposite charges attract.
The further away two charged objects are the weaker the electrical force between them.
The closer two charged objects are the stronger the electrical force between them.
Hope this helps :)</span>

Varvara68 [4.7K]3 years ago

4 0

Answer:

Option (2), (4), (6)

Explanation:

According to the properties of charges, two like charges repel each other and two unlike charges attract each other.

If two positive or two negative charges kept at a distance, then they repel each other.

If one positive and one negative charges kept at a distance, they always attract each other.

Now according to the Coulomb's law, the force between the two charges, is directly proportional to the product of two charges and inversely proportional to the square of distance between them.

So, farther the two charges, weaker is the force.

And closer the two charges, stronger is the force.

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The quantity of charge Q in coulombs (C) that has passed through a point in a wire up to time t (measured in seconds) is given b

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Explanation:

The quantity of charge Q in coulombs (C) that has passed through a point in a wire up to time t (measured in seconds) is given by :

$Q=t^3-2t^2+4t+4$

We need to find the current flowing. We know that the rate of change of electric charge is called electric current. It is given by :

$I=\dfrac{dQ}{dt}\\\\I=\dfrac{d(t^3-2t^2+4t+4)}{dt}\\\\I=3t^2-4t+4$

At t = 1 s,

Current,

$I=3(1)^2-4(1)+4\\\\I=3\ A$

So, the current at t = 1 s is 3 A.

For lowest current,

$\dfrac{dI}{dt}=0\\\\\dfrac{d(3t^2-4t+4)}{dt}=0\\\\6t-4=0\\\\t=0.67\ s$

Hence, this is the required solution.

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3 years ago

In a college homecoming competition, eighteen students lift a sports car. While holding the car off the ground, each student exe

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Answer:

Explanation:

Given

Each student exert a force of $F=400 N$

Let mass of car be m

there are 18 students who lifts the car

Total force by 18 students $F=18\times 400=7200 N$

therefore weight of car $W=7200$

mass of car $m=\frac{W}{g}$

$m=\frac{7200}{9.8}=734.69 kg$

(b) $7200 N \approx 1618.624\ Pound-force$

$734.69 kg\approx 1619.71 Pounds$

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2 years ago

Which material would you take, steel or bricks to design a bridge? Why?

Vesna [10]

Answer:

steel

Explanation:

steel because steel has more power to hold something up, where bricks arent as stable

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2 years ago

Read 2 more answers

15. If an 800.-kg sports car slows to 13.0 m/s to check out an accident scene and the

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The final combined velocity after the collision is 20.2 m/s

Explanation:

We can solve this problem by using the law of conservation of momentum: in fact, in absence of external forces, the total momentum of the two car and of the truck must be conserved before and after the collision.

This means that we can write the following equation:

$p_i = p_f\\m_1 u_1 + m_2 u_2 = (m_1+m_2)v$