Answer:
a) 5.57 m/s
b) 403 N
Explanation:
We will find the radius, r of the motion using the formula
r = radius of the platform + horizontal swing distance
r = diameter/2 + Lsinθ, where L is the length of the massless chain and θ is the displaced angle
r = 8.03/2 + 3.76 sin28.6
r = 4.015 + 1.8
r = 5.82 m
a) To get the speed, we use the formula
tanθ = v2/rg, if we make v subject of formula, we have
v = √(rgtanθ), where
v = speed of the seats
g = 9.8m/s²
v = √(5.82 * 9.8 * tan28.6)
v = √(5.82 * 9.8 * 0.545)
v = √31.08
v = 5.57 m/s
b) To find the tension, we use the formula
Tcosθ = mg, making T subject of formula, we have
T = mg/cosθ, where T = tension in the chain and m = 10 kg + 26.2 kg = 36.2 kg and θ = 28.6°
T = 36.2 * 9.8 / cos 28.6
T = 354.76 / 0.88
T = 403 N
