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3 years ago

1.Mention two uses of the concave mirror.

Physics

1 answer:

Anuta_ua [19.1K]3 years ago

8 0

Answer:

1. telescope

$f = \frac{r}{2}$

$f = \frac{r}{2}$ f- focal length

$f = \frac{r}{2}$ f- focal length r- the radius of curvature of the mirror

$\frac{1}{f} = \frac{1}{p} + \frac{1}{l}$

p-the distance of the object from the vertex of the mirror

l-the distance of the figure from the vertex of the mirror

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A current-carrying wire of length 52.0 cm is positioned perpendicular to a uniform magnetic field. If the current is 15.0 A and

nata0808 [166]

Answer:

The magnetic field strength is 0.29 T.

Explanation:

Given that,

Length of current-carrying wire, L = 52 cm = 0.52 m

Current, I = 15 A

Magnetic force, F = 2.3 N

We need to find the magnetic field strength. We know that the magnetic force is given by :

$F=ILB$

B is magnetic field strength

$B=\dfrac{F}{IL}\\\\B=\dfrac{2.3}{0.52\times 15}\\\\B=0.29\ T$

So, the magnetic field strength is 0.29 T.

6 0

3 years ago

At its peak, a tornado is 53.0 m in diameter and carries 465-km/h winds. What is its angular velocity in revolutions per second?

expeople1 [14]

Answer:

0.7757 rev/s

Explanation:

d = Diameter of the tornado = 53 m

r = Radius of the tornado = 53/2 = 26.5 m

v = Velocity of wind = 465 km/h

Converting velocity to m/s

$465=465\times \frac{1000}{3600}=\frac{775}{6}$

Angular velocity

$\omega=\frac{v}{r}\\\Rightarrow \omega=\frac{\frac{775}{6}}{26.5}\\\Rightarrow \omega=4.87\ rad/s$

$\omega=4.87\frac{1}{2\pi}=0.7757\ rev/s$

∴ Angular velocity is 0.7757 rev/s

8 0

3 years ago

How does charging by conduction occur?

lutik1710 [3]

Answer : (A) A charged object is brought near a neutral object without touching it.

Explanation:

Bodies can be charged by the method of conduction. By conduction the body acquires the same charge as on the charging body.

Charging the body can be understood by the following example of charging a paper cylinder by conduction. Make a paper cylinder by rolling a strip of paper on a pencil and then gently pulling out the pencil. Suspend the paper cylinder by a string tied to its center, now touch the paper cylinder with a glass rod rubbed with silk so it has a positive charge. Remove the class rod and the again bring it near to the paper cylinder.

The paper cylinder is repelled by the positively charged rod. And when you bring a negatively rubbed rod, next to the cylinder it will be attracted towards the rod. This means that the paper cylinder has acquired a positive charge as on the glass rod due to conduction.

8 0

3 years ago

A circuit is constructed with six resistors and two batteries as shown. The battery voltages are V1 = 18 V and V2 = 12 V. The po

kaheart [24]

The I3 will be 158 A.

<h3>How to find the current through the circuit?</h3>

The foundation of circuit analysis is Kirchhoff's circuit laws.
We have the fundamental instrument to begin studying circuits with the use of these principles and the equation for each individual component (resistor, capacitor, and inductor).
These rules aid in calculating the current flow in various network streams as well as the electrical resistance of a complicated network, or impedance in the case of AC.

To calculate I3 firstly, V4 has to be calculated,

$V_{4} =I_{4} R_{4}$