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steposvetlana [31]
2 years ago
13

There are four springs stretched by the same mass.

Physics
1 answer:
brilliants [131]2 years ago
8 0

Spring C stretches 100 cm.

Explanation:

The spring constant is simply the stiffness of the spring. The higher the spring constant the more stiff the spring is.

Spring constant shows the force needed to stretch a spring from it's equilibrium position. If a material requires more force to cause it to stretch, it will have a high spring constant.

          According to hooke's law "the force needed to extended an elastic material is directly proportional to its extension"

          F = ke

   k is the spring constant

   e is the extension

We see that the spring that stretches by 100 is the less stiff compared to other springs. It has the smallest spring constant.

Learn more;

Force brainly.com/question/8882476

#learnwithBrainly

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Mashcka [7]

Answer:

for 4.567 I can't tell if it x 10^{3} or x 10^{5} so:

answer using x 10^{3} = 0.0000644697N

answer using x 10^{5} = 0.00644697

Explanation:

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2 years ago
A hot-air balloon is rising upward with a constant speed of 2.85 m/s. When the balloon is 2.50 m above the ground, the balloonis
NISA [10]

Answer:

Explanation:

You have to declare which way is plus -- up or down. I will use down.

vi = - 2.85       The balloon is going up. That is the minus direction.

a = 9.81

d =   2.50 meters  distance in this case is from the object to the ground.

d = vi*t + 1/2 a t^2

-2.50 = -2.85*t + 1/2 * 9.81 * t^2

-2.50 = -2.85*t + 4.905 * t^2           transfer the left to the right.

-4.905 t^2 + 2.85*t + 2.50 = 0

Use the quadratic formula to solve for t.

It turns out that t = 1.06

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3 years ago
How does bilateral symmerty extend to our senses?​
andreev551 [17]

Answer:

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3 years ago
What mass of lead has the same volume as 1600kg of gasoline?
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2 years ago
Diagram shows the velocity time graph for a particle moving in 16 seconds.
Leya [2.2K]

Answer:

The detailed calculations are shown below;

Explanation:

a)The maximum acceleration of the particle:

  It is seen that the maximum change in velocity is at the time between 8s to 10s.

              Maximum acceleration: \frac{V}{t}

                                                    = \frac{20}{2}

                                                    = 10 m/s^{2}

b) The deceleration of the particle

          The velocity of particle is decreased after 10s so,

                     deceleration = - \frac{40}{6}

                                           = - 6.67 m/s^{2}

c)The total distance traveled by the particle = Area under the curve

                               = \frac{1}{2}* 4*20 + 4*20 +  \frac{1}{2}* 2*20+ 2*20+ \frac{1}{2}* 40*16

                                                       = 290 m

d)The average velocity of the particle = \frac{Area under the curve}{Total time}

                                                               = \frac{290}{16}

                                                               = 18.12 m/s

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3 years ago
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