Question

At a distance of 0.208 cm from the center of a charged conducting sphere with radius 0.100cm, the electric field is 485 n/c . what is the electric field 0.620 cm from the center of the sphere?

Answer 1

Solution:

we have given that the following:-

d=0.208cm

r=0,1cm

E=485N/C

we have to find at r=0.620cm

thus for the calculation of that we have to suppose the imaginary surface of sphere

Imaginary surfaces are spheres of radii 0.208cm and 0.620cm  

485x4π 0.198²=E'x4π 0.586²  

so,

E'.= 485x4π 0.198²/4π 0.586²

      =19.01394/0.34396

      = 55.37NC.

Answer 2

We have the equation for electric field E = kQ/$d^{2}$

Where k is a constant, Q is the charge of source and d is the distance from center.

In this case E is inversely proportional to $d^{2}$

So, $\frac{E_{1} }{E_{2}} = \frac{d_{2}^{2}}{d_{1}^{2}}$

$E_{1}$ = 485 N/C

$d_{1}$ = 0.208 cm

$d_{2}$ = 0.620 cm

$E_{2}$ = ?

$\frac{485 }{E_{2}} = \frac{0.620^{2}}{0.208^{2}}$

$E_{2}$ = $\frac{485*0.208^{2}}{0.628^{2}}$

$E_{2}$ = 53.20 N/C