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dimulka [17.4K]
1 year ago
10

A motorist drives along a straight road at a constant speed of 15 m/s. just as she passes aparked motorcycle police officer , th

e officer starts to accelerate at 2m/s2 to over take her. assuming the officer maintains this acceleration,
a) determine the time it takes the police to reach the motorist the speed and
b) the total displacement of the officer as he overtakes the motorist
Physics
1 answer:
allsm [11]1 year ago
4 0

Explanation:

Distance traveled by motorist =(15.0m/s)t

Distance traveled by policeman =1/2(2.00m/s2)t2

(a) Intercept occurs when 15.0t =t2or t=15.0s.

(b) x(officer)=1/2(2.00m/s2)t2= 225m

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kramer
<span>If there isn't any force then the normal contact force will be 


N=m*g=7.5*9.81=73.58N 

which is 73.58-23=50.58N less 

so, there the person must pull at 23 degree upward 

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vertical tension= 50.58=T*sin23 

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7 0
3 years ago
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Two tugboats pull a disabled supertanker. Each tug exerts a constant force of 1.8×106N , one an angle 11degrees west of north an
sp2606 [1]

Answer: 2,9 ×10¹⁰J.

Explanation:

1. The <em><u>work </u></em>is a measure of energy and is calculated as the product of the displacement times the parallel force to such displacement.

That means that the only components of the force that contribute to work are those that result parallel to the displacement.

2. Since it is given that the <em>two tugboats "pull the tanker a distance 0.83km toward the north"</em>, that is the displacement, and you have to calculate the net force toward the north.

3. <u>Tugboat #1</u>.

a) Force magnitude: F₁ = 1.8×10⁶N

b) Angle: α = 11° West of North

c) North component of the force F₁: Fy₁ = F₁cos(α) =  1.8×10⁶N  × cos(11°) = 1.77×10⁶N

4. <u>Tugboat #2</u>:

a) Force magnitude: F₂ = 1.8×10⁶N

b) Angle:  = 11° East of North

c) North component of the force F₂: Fy₂ = F₂cos(β) =  1.8×10⁶N  × cos(11°) = 1.77×10⁶N =

5. <u>Total net force, Fn</u>:

Fn = Fy₁ + Fy₂ = 1.77×10⁶N + 1.77×10⁶N = 3.54×10⁶N

6. <u>Work, W</u>:

Displacement, d = 0.83 km = 8,300 m

W = Fn×d = 3.54×10⁶N×8,300m = 29,000 ×10⁶J = 2,9 ×10¹⁰J

The answer is rounded to two significant figures because both data, Force and displacement, have two significant figures.

7 0
3 years ago
A _____ space zone is one that is obstructed in some way
telo118 [61]
A closed space zone is one that is obstrutced in some way.

Hope this helps :)
5 0
3 years ago
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As you may well know, placing metal objects inside a microwave oven can generate sparks. Two of your friends are arguing over th
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Answer:

5.04\cdot 10^8 A

Explanation:

The work function of the metal corresponds to the minimum energy needed to extract a photoelectron from the metal. In this case, it is:

\phi = 3.950\cdot 10^{-19}J

So, the energy of the incoming photon hitting on the metal must be at least equal to this value.

The energy of a photon is given by

E=\frac{hc}{\lambda}

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c is the speed of light

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Using E=\phi and solving for \lambda, we find the maximum wavelength of the radiation that will eject electrons from the metal:

\lambda=\frac{hc}{E}=\frac{(6.63\cdot 10^{-34} Js)(3\cdot 10^8 m/s)}{3.950\cdot 10^{-19} J}=5.04\cdot 10^{-7}m

And since

1 angstrom = 10^{-15}m

The wavelength in angstroms is

\lambda=\frac{5.04\cdot 10^{-7} m}{10^{-15} m/A}=5.04\cdot 10^8 A

3 0
3 years ago
The work done on a box is 532 joules. The force applied to the box was 48 N. What was the displacement of the box? *
Semenov [28]

Explanation:

Work = force × displacement

532 J = 48 N × d

d ≈ 11 m

8 0
3 years ago
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