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dimulka [17.4K]
1 year ago
10

A motorist drives along a straight road at a constant speed of 15 m/s. just as she passes aparked motorcycle police officer , th

e officer starts to accelerate at 2m/s2 to over take her. assuming the officer maintains this acceleration,
a) determine the time it takes the police to reach the motorist the speed and
b) the total displacement of the officer as he overtakes the motorist
Physics
1 answer:
allsm [11]1 year ago
4 0

Explanation:

Distance traveled by motorist =(15.0m/s)t

Distance traveled by policeman =1/2(2.00m/s2)t2

(a) Intercept occurs when 15.0t =t2or t=15.0s.

(b) x(officer)=1/2(2.00m/s2)t2= 225m

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How do you calculate percentage uncertainties???
ch4aika [34]


I is just the uncertainty over the actual number multiplied by 100.


example:

36.1( +/- 0.1)

The percentage of the uncertainty here is 0.1/36.1x 100=0.3%

5 0
3 years ago
How dose the speed of the sound differ in water, iron, and Helium?
stepladder [879]

Answer:

             air       water      iron        helium

v(m/s)   280     2200      17780     39682

Explanation:

The speed of a wave depends on the physical properties of the medium where it travels, in the case of a longitudinal wave such as sound, it depends on the resistance to deformation (volume modulus and the density of the medium

         v = \sqrt{ \frac{B}{ \rho } }

in the mentioned materials they are constant  

             air       water      iron        helium

B           1 10⁵    2.2 10⁹    140 10⁹   0.05 10⁹

ρ           1.28     997        7874       1.26

v(m/s)   280     2200      17780     39682

4 0
3 years ago
Vocabulary
katrin2010 [14]
We don’t have the terms
8 0
2 years ago
Vector c has a magnitude 24.6 m and is in the direction of the negative y-axis. vectors a and b are at angles α = 41.4° and β
storchak [24]
The vector c has a magnitude of 24.6m and it is in the negative y direction. Therefore
\vec{c} = - 24.6 \hat{j}

The vector b is 41.4° up from the x-axis. Therefore
\vec{b} = b[cos(41.4^{o}) \hat{i} + sin(41.4^{o}) \hat{j} ] =b(0.75\hat{i} + 0.6613 \hat{j})

The vector a is 27.7° up from the x-axis. Therefore
\vec{a} = a[cos(22.7^{o})\hat{i} + sin(27.7^{o})\hat{j}] =  a(0.8854\hat{i} + 0.4648\hat{j})

Because \vec{a} +\vec{b} + \vec{c} = 0, the sum of the x and y components should be zero. Therefore,
For the x-component,
0.8854a + 0.75b = 0
 or
 a + 0.847b = 0                            (1)
For the y-component,
0.4648a + 0.6613b - 24.6 = 0
 or
 a + 1.4228b = 52.926                (2)

Subtract (1) from (2).
0.5758b = 52.926
b = 91.917
a = -0.847b = -77.854

Answer:
The magnitude of vector a is -77.85 m
The magnitude of vector b is 91.92 m
5 0
3 years ago
To apply Problem-Solving Strategy 12.2 Sound intensity. You are trying to overhear a most interesting conversation, but from you
Ivenika [448]

Answer:

r₂ = 0.316 m

Explanation:

The sound level is expressed in decibels, therefore let's find the intensity for the new location

            β = 10 log \frac{I}{I_o}

let's write this expression for our case

           β₁ = 10 log \frac{I_1}{I_o}

           β₂ = 10 log \frac{I_2}{I_o}

           

          β₂ -β₁ = 10 ( log \frac{I_2}{I_o} - log \frac{I_1}{I_o})

          β₂ - β₁ = 10 log \frac{I_2}{I_1}

          log \frac{I_2}{I_1} = \frac{60 - 20}{10} = 3

           \frac{I_2}{I_1} = 10³

           I₂ = 10³ I₁

having the relationship between the intensities, we can use the definition of intensity which is the power per unit area

           I = P / A

           P = I A

the area is of a sphere

          A = 4π r²

           

the power of the sound does not change, so we can write it for the two points

          P =  I₁ A₁ =  I₂ A₂

          I₁ r₁² = I₂ r₂²

we substitute the ratio of intensities

          I₁ r₁² = (10³ I₁ ) r₂²

         r₁² = 10³ r₂²

         

         r₂ = r₁ / √10³

         

we calculate

          r₂ = \frac{10.0}{\sqrt{10^3} }

          r₂ = 0.316 m

8 0
3 years ago
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