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polet [3.4K]
2 years ago
7

if you dig a hole through the earth, from one hemisphere to the other, and drop a tennis ball into it, would it get stuck at the

center, since thats where gravity's at, or would it pop up out the other side??
Physics
2 answers:
tia_tia [17]2 years ago
7 0

Answer:

Depending on which hemisphere it is, like western to eastern, It would most likely get stuck at the center. You would also have to put more things into thought like acceleration, velocity, and speed.

BUT since the question asked "would it pop out the other side?", I'm assuming it's talking about northern to southern hemisphere. so in that case it would pop out the other side since gravity makes things go downwards.

kodGreya [7K]2 years ago
6 0

Answer:

We drop a tennis ball into the hole. The stone is pulled down towards the center of the earth. It falls all the way to the middle of the earth once it reaches the middle, theres no more pull of gravity. ... It would go up a ways, then (due to the pull of gravity) fall back in the other direction, back towards the center

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Three 7 0hm resistors are connected in series across a 10 V battery. What is the equivalent resistance of the circuit?
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Given

Three 7 ohm resistor are in series.

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To find

The equivalent resistance

Explanation

When the resistance are in series then the resistance are added to find its equivalent.

Thus the equivalent resistance is:

R=7+7+7=21\Omega

Conclusion

The equivalent resistance is 21 ohm

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a sound pulse emitted underwater reflects off a school of fish and is detected at the same place 0.01 s later. how far away are
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I don’t get it I need help
5 0
3 years ago
a body of a mass 1kg suspended from a spring is found to stretch the spring by 10cm. (A) what is the spring constant? what is pe
Nikitich [7]

Answer:

(A) The spring constant is <u>98 N/m.</u>

(B) The period of oscillation is <u>0.635 s.</u>

Explanation:

Given:

Mass of the body is, m=1\ kg

Extension length of the spring is, x=10\ cm=0.1\ m

Now, let 'k' be the spring constant.

The force acting on the body is due to gravity only and is equal to its weight.

So, weight of the body is given as:

F_g=mg\\F_g=1\times 9.8\\F_g=9.8\ N

Now, we know that for a spring-mass system, the net force acting on the body is equal to the product of the spring constant and extension length. Therefore,

F_g=kx\\9.8=k(0.1)\\k=\frac{9.8}{0.1}=98\ N/m

Hence, the spring constant is 98 N/m.

(B)

Period of oscillation of a body of spring-mass system in SHM is given as:

T=2\pi\sqrt{\frac{m}{k}}

Plug in the given values and solve for period 'T'. This gives,

T=2\pi\sqrt{\frac{1}{98}}\\T=2\pi\times 0.101\\T=0.635\ s

Therefore, the period of oscillation is 0.635 s.

5 0
3 years ago
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