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crimeas [40]
3 years ago
10

1. Part 2: Single-Displacement Reactions: For each of the four single-displacement reactions, write a balanced equation. Assume

that there will be a reaction even if you didn't see one in the lab. General equation for single-displacement reactions:
A + BX → AX + B

Ion charges: (Zn2+, Cu2+, SO42-, Al3+, Ag1+, NO31-) Answer: • zinc [Zn] + copper sulfate [Cu(SO4)] (2 points) ◦

Balanced equation: … + … → …. + …. • aluminum [Al] + copper sulfate [Cu(SO4)] (2 points) ◦

Balanced equation: … + … → …. + …. • zinc [Zn] + silver nitrate [Ag(NO3)] (2 points)

◦ Balanced equation: … + … → …. + …. • copper [Cu] + silver nitrate [Ag(NO3)] (2 points) ◦ Balanced equation: … + … → …. + ….
Chemistry
1 answer:
natima [27]3 years ago
6 0
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

- zinc [Zn] + copper sulfate [Cu(SO4<span>)
</span>Balanced equation:Zn + Cu(SO4) → Zn(SO4<span>) + Cu

- </span>aluminum [Al] + copper sulfate[Cu(SO4)]Balanced equation:2Al + 3Cu(SO4) → Al2(SO4)3<span>+ 3Cu

-  </span>zinc [Zn] + silver nitrate [Ag(NO3)]Balanced equation:Zn + 2Ag(NO3) → 2Ag + Zn(NO3)<span>2

- </span>copper [Cu] + silver nitrate [Ag(NO3)]
Balanced equation:Cu + Ag(NO3) → Cu(NO3<span>) + Ag</span>
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How many grams of solute are needed to make 37.5 mL of 0.750 M KI solution? Round to three significant digits.
Marysya12 [62]

4.648 gm of solute is needed to make 37.5 mL of 0.750 M KI solution.

Solution:  

We will start with the Molarity  

\text { Molarity }=\text { Mole of solute } \div \text { liter of solution }

Also we know 1000 ml = 1 L

Therefore 37.5 ml by 1000ml we obtained 0.0375L  

Equation for solving mole of solute

\text { Mole of solute }=\text { Molarity } \times \text { Liters of solution }

Now, multiply 0.750M by 0.0375

Substitute the known values in the above equation we get

0.750 \times 0.0375=0.0281

Also we know that Molar mass of KI is 166 g/mol

So divide the molar mass value to get the no of grams.

0.028 \times 166=4.648

So 4.648 gm of Solute is required for make 37.5 mL of 0.750 M KI solution.

8 0
3 years ago
How many mole of ZnCl2 will be produced from 55.0 g of Zn, assuming HCL is available in excess
Ilia_Sergeevich [38]

Answer:

0.84 mol

Explanation:

Given data:

Moles  of ZnCl₂ produced = ?

Mass of Zn = 55.0 g

Solution:

Chemical equation:

2HCl + Zn  →  ZnCl₂ + H₂

Number of moles of Zn:

Number of moles = mass / molar mass

Number of moles = 55.0 g/ 65.38 g/mol

Number of moles = 0.84 mol

Now we will compare the moles of Zn with ZnCl₂ from balance chemical equation.

                                      Zn          :             ZnCl₂

                                         1          :               1

                                      0.84       :           0.84

So from 55 g of Zn 0.84 moles of zinc chloride will be produced.

8 0
4 years ago
How does the electron structure of atoms change when they form chemical bonds
andriy [413]
For ionic bond
The metal atom will lose electrons to form cations and the non metal atom will gain electron.egNaCl
3 0
3 years ago
When two or more covalently bonded atoms combine chemically, we refer to the physical result as?
ale4655 [162]
It is referred as a covalent bond
6 0
4 years ago
Anyone in connections taking chemistry that can help me? P.S this IS a question so do not delete it.
iren [92.7K]
I suggest watching Martin Shkerli YouTube channel. He has a ton of videos on chemistry and is very helpful. 
6 0
3 years ago
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