Answer:
b) 5.87 E23 molecules
Explanation:
∴ mm SO3 = 80.066 g/mol
⇒ molecules SO3 = (78.0 g)(mol/80.066 g)(6.022 E23 molec/mol)
⇒ molec SO3 = 5.866 E23 molecules SO3
Answer:
0.07975 M NaOH
Explanation:
First determine the molarity of your acid, KHP. Convert grams to moles using the MW given and then divide by the volume of water.
0.3175 g KHP • (1 mol KHP / 204.2 g KHP) = 0.001555 mol KHP
0.001555 mol KHP / 0.040 L = 0.03888 M KHP
The reaction between KHP and NaOH is one-to-one, so you can just use M1V1 = M2V2 to solve for M2 (the molarity of NaOH).
M1 = 0.03888 M KHP
V1 = 40 mL
M2 = ? M NaOH
V2 = 19.45 mL NaOH
(0.03888 M KHP)(40 mL) = M2(19.5 mL NaOH)
M2 = 0.07975 M NaOH
People have died over drinking big amounts of water in fraternity initiations and while they where having the radio contest. So no there it's no life after hydration
<span>7.15 degrees C
The specific heat capacity of water is 4.1813 J/(g*K). So we have 3 values with the units kJ, g and J/(g*K). We can trivially convert from kJ to J by multiplying by 1000. And we want to get a result with the unit K (degrees Kelvin). So let's do it. First, let's cancel out the g unit by multiplying.
4.1813 J/(g*K) * 485 g = 2027.9305 J/K
Now we can cancel out the J unit by dividing. But if we divide by the energy, we'll be left with the reciprocal of K, not K. So instead divide by the J/K unit. So
14500 J / 2027.9305 J/K = 7.150146418 K
Rounding to 3 significant figures gives us 7.15 K.
And since degrees C and degrees K are the same size, the temperature will increase by 7.15 degrees C</span>
