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crimeas [40]
3 years ago
10

1. Part 2: Single-Displacement Reactions: For each of the four single-displacement reactions, write a balanced equation. Assume

that there will be a reaction even if you didn't see one in the lab. General equation for single-displacement reactions:
A + BX → AX + B

Ion charges: (Zn2+, Cu2+, SO42-, Al3+, Ag1+, NO31-) Answer: • zinc [Zn] + copper sulfate [Cu(SO4)] (2 points) ◦

Balanced equation: … + … → …. + …. • aluminum [Al] + copper sulfate [Cu(SO4)] (2 points) ◦

Balanced equation: … + … → …. + …. • zinc [Zn] + silver nitrate [Ag(NO3)] (2 points)

◦ Balanced equation: … + … → …. + …. • copper [Cu] + silver nitrate [Ag(NO3)] (2 points) ◦ Balanced equation: … + … → …. + ….
Chemistry
1 answer:
natima [27]3 years ago
6 0
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

- zinc [Zn] + copper sulfate [Cu(SO4<span>)
</span>Balanced equation:Zn + Cu(SO4) → Zn(SO4<span>) + Cu

- </span>aluminum [Al] + copper sulfate[Cu(SO4)]Balanced equation:2Al + 3Cu(SO4) → Al2(SO4)3<span>+ 3Cu

-  </span>zinc [Zn] + silver nitrate [Ag(NO3)]Balanced equation:Zn + 2Ag(NO3) → 2Ag + Zn(NO3)<span>2

- </span>copper [Cu] + silver nitrate [Ag(NO3)]
Balanced equation:Cu + Ag(NO3) → Cu(NO3<span>) + Ag</span>
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What volume will 3.0 moles of O2 gas occupy at S.T.P?
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Explanation:

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During a class demonstration the potassium exploded. Suggest what might have caused this to happen
tatiyna
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7 0
3 years ago
A certain compound has the following percent composition: 57.1% C, 4.8% H, and 38.l% O.
crimeas [40]

Answer:

C₆H₆O₃

Explanation:

Calculation sequence:

% => grams => moles => reduce => empirical Ratio

Molecular multiple = Molecular Mass / Empirical Mass

  C: => 57.1% => 57.1 g => 57.1/12 = 4.7583

  H: =>  4.8% =>  4.8 g =>   4.8/1  = 4.8000

  O: => <u>38.1% => 38.1 g </u>=> 38.1/16 = 2.3813

TTL => 100%       100 g

Reduced Mole values =>

C : H : O => 4.7583/2.3813 : 4.8000/2.3813 : 2.3813/2.3813 => 2 : 2 :  1

∴ empirical formula => C₂H₂O

empirical formula weight => 2C + 2H + 1O = [2(12) + 2(1) + 1(16)] amu = 42 amu

molecular formula weight (given in problem) = 126 g/mole

The molecular formula is a whole number multiple of the empirical formula.

molecular multiple = 126 amu / 42 amu = 3

∴ molecular formula => (C₂H₂O)₃ => C₆H₆O₃

8 0
3 years ago
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