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crimeas [40]
3 years ago
10

1. Part 2: Single-Displacement Reactions: For each of the four single-displacement reactions, write a balanced equation. Assume

that there will be a reaction even if you didn't see one in the lab. General equation for single-displacement reactions:
A + BX → AX + B

Ion charges: (Zn2+, Cu2+, SO42-, Al3+, Ag1+, NO31-) Answer: • zinc [Zn] + copper sulfate [Cu(SO4)] (2 points) ◦

Balanced equation: … + … → …. + …. • aluminum [Al] + copper sulfate [Cu(SO4)] (2 points) ◦

Balanced equation: … + … → …. + …. • zinc [Zn] + silver nitrate [Ag(NO3)] (2 points)

◦ Balanced equation: … + … → …. + …. • copper [Cu] + silver nitrate [Ag(NO3)] (2 points) ◦ Balanced equation: … + … → …. + ….
Chemistry
1 answer:
natima [27]3 years ago
6 0
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

- zinc [Zn] + copper sulfate [Cu(SO4<span>)
</span>Balanced equation:Zn + Cu(SO4) → Zn(SO4<span>) + Cu

- </span>aluminum [Al] + copper sulfate[Cu(SO4)]Balanced equation:2Al + 3Cu(SO4) → Al2(SO4)3<span>+ 3Cu

-  </span>zinc [Zn] + silver nitrate [Ag(NO3)]Balanced equation:Zn + 2Ag(NO3) → 2Ag + Zn(NO3)<span>2

- </span>copper [Cu] + silver nitrate [Ag(NO3)]
Balanced equation:Cu + Ag(NO3) → Cu(NO3<span>) + Ag</span>
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If there are 3.10 moles of O, how many moles of each of the compounds are present?
Burka [1]

Explanation:

The question pretty  much requires us to find the amount of moles of each compounds based on the number of moles of O given.

H2SO4

1 mol of H2SO4 contains 4 mol of O

x mol of H2SO4 would contain 3.10 mol of O

x = 3.10 * 1 / 4 = 0.775 mol of H2SO4

C2H4O2

1 mol of C2H4O2 contains 2 mol of O

x mol of C2H4O2 would contain 3.10 mol of O

x = 3.10 * 1 / 2 = 1.55 mol of C2H4O2

NaOH

1 mol of NaOH contains 1 mol of O

x mol of NaOH would contain 3.10 mol of O

x = 3.10 * 1 / 1 = 3.10 mol of NaOH

3 0
3 years ago
What is the electron configuration for the Magnesium ion?​
soldi70 [24.7K]
1s^2 2s^2 2p^6 for the Mg2+ ion.
4 0
2 years ago
When 100 mL of 0.200 M NaCl(aq) and 100 mL of 0.200 M AgNO3(aq), both at 21.9 °C, are mixed in a coffee cup calorimeter, the tem
masya89 [10]

Answer:

There is 1.3 kJ heat produced(released)

Explanation:

<u>Step 1:</u> Data given

Volume of a 0.200 M Nacl solution = 100 mL = 0.1 L

Volume of a 0.200 M AgNO3 solution = 100 mL = 0.1 L

Initial temperature = 21.9 °C

Final temperature = 23.5 °C

Solid AgCl will be formed

<u>Step 2</u>: The balanced equation:

AgNO3(aq) + NaCl(aq) → AgCl(s) + NaNO3(aq)

AgCl(s) + NaNO3(aq) → Na+(aq) + NO3-(aq) + AgCl(s)

<u>Step 3:</u> Define the formula

Pressure is constant.  → the heat evolved from the reaction is equivalent to the enthalpy of reaction.  

Q=m*c*ΔT

⇒ Q = the heat transfer (in joule)

⇒ m =the mass (in grams)

⇒ c= the heat capacity (J/g°C)

⇒ ΔT = Change in temperature = T2- T1

Step 4: Calculate heat

Let's vonsider the density the same as the density of water (1g/mL)

Mass = volume * density

Mass = 200 mL * 1g/mL

Mass = 200 grams

Q= m*c*ΔT

⇒ m = 200 grams

⇒ c = the heat capacity (let's consider the heat capacity of water) = 4.184 J/g°C

⇒ ΔT = 23.5 -21.9 = 1.6°C

Q = 200 * 4.184 * 1.6 = 1338 .9 J = 1.3 kJ

There is 1.3 kJ heat produced(released)

Therefore, we assumed no heat is absorbed by the calorimeter, no heat is exchanged between the  calorimeter and its surroundings, and the specific heat and mass of the solution are the same as those for  water (1g/mL and 4.184 J/g°C)

7 0
3 years ago
Which property of water makes it effective in protecting firefighters?
bezimeni [28]

Answer:

water has a high specific heat

Explanation:

this should work as an answer

5 0
2 years ago
People take antacids, such as milk of magnesia, to reduce the discomfort of acid stomach or heartburn. The recommended dose of m
Llana [10]

Answer:

V_{HCl}=0.208L=208mL

Explanation:

Hello,

In this case, since the chemical reaction is:

2HCl+Mg(OH)_2\rightarrow MgCl_2+2H_2O

We can see that hydrochloric acid and magnesium hydroxide are in a 2:1 mole ratio, which means that the neutralization point, we can write:

n_{HCl}=2*n_{Mg(OH)_2}

In such a way, the moles of magnesium hydroxide (molar mass 58.3 g/mol) in 500 mg are:

n_{Mg(OH)_2}=500mg*\frac{1g}{1000mg}*\frac{1mol}{58.3g}  =0.00858mol

Next, since the pH of hydrochloric acid is 1.25, the concentration of H⁺ as well as the acid (strong acid) is:

[H^+]=[HCl]=10^{-pH}=10^{-1.25}=0.0562M

Then, since the concentration and the volume define the moles, we can write:

[HCl]*V_{HCl}=2*n_{Mg(OH)_2}

Therefore, the neutralized volume turns out:

V_{HCl}=\frac{2*0.00858mol}{0.0562\frac{mol}{L} }\\ \\V_{HCl}=0.208L=208mL

Best regards.

3 0
3 years ago
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