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Licemer1 [7]
3 years ago
7

Question 21 of 25

Chemistry
1 answer:
RideAnS [48]3 years ago
7 0

Answer:

7

Explanation:

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The amount of calories you weight
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How do metals become stable?
natali 33 [55]

Answer:

Atoms of metal elements give away electrons in their reactions to form positive ions. The ions formed have a full outer electron shell, so are very stable.

Explanation:

To become stable, the metal atom wants to get rid of one or more electrons in its outer shell. ... Alternately, an atom that loses electrons becomes a positively charged ion (aka cations). The particles in an ionic compound are held together because there are oppositely charged particles that are attracted to one another.

8 0
3 years ago
Please help me !!!!!!!!! <br> i'll give brainlist !
qwelly [4]

Answer:

A-B

C-D

E-F

I think it's these because Potential Energy increase when the graph increases and remain constant when the graph is flat.

8 0
3 years ago
The following molecular equation represents the reaction that occurs when aqueous solutions of silver(I) nitrate and calcium chl
dsp73

Answer:

Ag+(aq) + Cl-(aq) —> AgCl(s)

Explanation:

2AgNO3(aq) + CaCl2(aq) —>2AgCl(s) + Ca(NO3)2(aq)

The balanced net ionic equation for the reaction above can be obtained as follow:

AgNO3(aq) and CaCl2(aq) will dissociate in solution as follow:

AgNO3(aq) —> Ag+(aq) + NO3-(aq)

CaCl2(aq) —> Ca2+(aq) + 2Cl-(aq)

AgNO3(aq) + CaCl2(aq) –>

2Ag+(aq) + 2NO3-(aq) + Ca2+(aq) + 2Cl-(aq) —> 2AgCl(s) + Ca2+(aq) + 2NO3-(aq)

Cancel out the spectator ions i.e Ca2+(aq) and 2NO3- to obtain the net ionic equation.

2Ag+(aq) + 2Cl-(aq) —> 2AgCl(s)

Divide through by 2

Ag+(aq) + Cl-(aq) —> AgCl(s)

The, the net ionic equation is

Ag+(aq) + Cl-(aq) —> AgCl(s)

4 0
3 years ago
Pleaaase argent !!! Explain ur answers
shtirl [24]

Answer:

1. Dynamic equilibrium is a equilibrium in which the rate of forward direction is equal to the rate of backward direction. It is represented by a right left arrow.

2) Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K_c  

For the given chemical reaction:

Fe^{3+}(aq)+SCN^-(aq)\rightleftharpoons [Fe(SCN)]^{2-}(aq)

The expression for K_c is written as:

K_c=\frac{[[Fe(SCN)]^{2-}]}{[Fe^{3+}][SCN^-]}

3) The value of K_c is 1000 , which means the products are more favoured as compared to reactants and that the equilibrium lies more towards product side.

4 0
3 years ago
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