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Delvig [45]
3 years ago
14

What does magnesium carbonate and hydrochloric acid make?

Chemistry
2 answers:
Lelechka [254]3 years ago
3 0

Answer:

Magnesium carbonate reacts with hydrochloric acid to produce magnesium chloride, carbon dioxide, and water.

Explanation:

CMgO3 + 2HCl  => MgCl2 +  CO2  +  H20

erastovalidia [21]3 years ago
3 0

Answer:

MgCO3 + HCl  Forms MgCl2 +  CO2  +  H20

Explanation:

It forms Megnesium chloride, carbon dioxide, and water.

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Use the unbalanced equation NH3 + O2 = NO + H2O
Elodia [21]
<span>The balance format is
4NH3+ 5O2 -------> 4NO + 6H2O </span>
7 0
3 years ago
43 mg = [?]g <br>A. 0.043 g <br>B. 4.3 g <br>C. 4300 g <br>D. 43,000 g​
Ymorist [56]

Answer:

Option A (0.043 g) is the correct answer.

Explanation:

Given:

= 43 mg

As we know,

1 \ mg = \frac{1}{1000} \ g

then,

⇒ 43 \ mg = \frac{43}{1000}  \ g

              = 0.043 \ g

Thus, the above is the correct alternative.

4 0
3 years ago
2. How many grams of NaCl are required to prepare 0.40 L of a 0.75 M solution?
Yuri [45]

The mass of a NaCl solution that is required to prepare 0.40 L of a 0.75 M solution is 17.55g. Details about mass can be found below.

<h3>How to calculate mass?</h3>

The mass of a substance can be calculated by multiplying the number of moles by its molar mass.

However, the number of moles of a solution must be initially calculated by using the following formula:

molarity = no of moles ÷ volume

no of moles = 0.75 × 0.40

no of moles = 0.3 moles

mass of NaCl = 0.3 × 58.5 = 17.55g

Therefore, the mass of a NaCl solution that is required to prepare 0.40 L of a 0.75 M solution is 17.55g.

Learn more about mass at: brainly.com/question/19694949

#SPJ1

4 0
1 year ago
Calculate the molarity of (3.25 mol of LiCl in 2.78 L solution
alisha [4.7K]

\text{Morality}= \dfrac{\text{Number of moles}}{\text{Volume}}=\dfrac{3.25}{2.78}=1.169 ~mol/L

8 0
2 years ago
The volume of the earth is approximately 1.08326x10 to the 12th power km to the 3rd power. How many liters is this
mafiozo [28]

Here, we are required to determine the volume of the earth which is 1.08326 × 10¹² km³ in liters.

<em>The volume of the earth is approximately</em>,

, 1.08326 × 10²⁴ liters

By conversion factors;

  • <em>1dm³ = 1liter</em>
  • However; <em>1km = 10000dm = 10⁴ </em><em>dm</em>
  • Therefore, 1km³ = (10⁴)³ dm³.

Consequently, 1km³ = 10¹²dm³ = 10¹²liters.

The conversion factor from 1km³ to liters is therefore, c.f = 10¹²liters/km³

Therefore, the volume of the earth which is approximately, 1.08326 × 10¹² km³ can be expressed in liters as;

<em>1.08326 × 10¹² km³ × 10¹²liters/km³ </em>

The volume of the earth is approximately,

1.08326 × 10²⁴ liters.

Read more:

brainly.com/question/16814684

7 0
2 years ago
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