All categories

3 years ago

HELP ASAP PLZ GUYS!!!!!! THANKS IN ADVANCED WILL MARK BRAILEST... 12 POINTS

Mathematics

2 answers:

Gnesinka [82]3 years ago

8 0

The answer is Y=40x

nordsb [41]3 years ago

6 0

Answer:

Truck B is going 40 miles /hour

Answer A

Step-by-step explanation:

First of all the equation is going to be of the form y = ax just as "a" is. You need a couple of points. The question you need to answer is this "Is the slope more or less than 55?" You don't really know because the point are not labeled in any way that would give you an answer.

Rules and Line A

So you have to make up a mini problem that will tell you what is going on. It does not matter what units you choose at all, just as long as you are consistent with both graphs. So let's assume each square is worth 5 mph going up the y axis. Let us further assume that each square on the x axis is one hour. So for line A if you go up 6 squares up the y axis and 5 units across, the slope will be 6*5 miles / 5 hours = 5 miles / hour

Line B

Now we work on the answer for the question by finding out what line B is doing. We choose the point where y axis has a value of 2 and the x axis is 3

The slope is then 5*2miles /3 hours = 3.3 which means that the vehicle for B is moving at a rate of 3.3 miles in 1 hour.

This does not represent anything in the real world. It is just to see if truck is moving faster or slower than truck A

Answer

Since the slope of line B is less than line A using my numbers, then Truck B must be travelling slower than line truck A.

Answer A is the only answer less than 55, so 40 mph must be the answer.

You might be interested in

If a man making $22 an hour gets a 20% raise, she will make an additional 1/10 of her salary an hour.

MariettaO [177]

Answer:

True

Step-by-step explanation:

If this is a true or false question it is true.

22 x 20% = 2.2

22 ÷ 10 = 2.2

Hope this helps!

3 0

3 years ago

What is the area of (10 times 8) (2x times 3x)

Phoenix [80]

Answer: 80 and 6x

Step-by-step explanation:

10 x 8 = 80

2x times 3x = 6x

3 0

3 years ago

The histogram below shows the distribution of times, in minutes, required for 25 rats in an animal behavior experiment to naviga

tino4ka555 [31]

Answer:

c. The median and the IQR (Interquartile range).

Step-by-step explanation:

Considering the histogram for the distribution of times for this experiment (see the graph below), we can notice that this distribution is skewed positively because of "a few scores creating an elongated tail at the higher end of the distribution" (Urdan, 2005). There is also a probable outlier (an animal that navigates around nine minutes). An outlier is an extreme value that is more than two standard deviations below or above the mean.

In these cases, when we have skewed and extreme values in a distribution, it is better to avoid using the mean and standard deviations as measures of central tendency and dispersion, respectively. Instead, we can use the median and the interquartile range for those measures.

With skewed distributions, the mean is more "sensible" to extreme data than the median, that is, it tends to not represent the most appropriate measure for central position (central tendency) in a distribution since in a positively skewed distribution like the one of the question, the mean is greater than the median, that is, the extreme values tend to pull the mean to them, so the mean tends to not represent a "reliable" measure for the central tendency of all the values of the experiments.

We have to remember that the dispersion measures such as the standard deviation and interquartile range, as well as the variance and range, provide us of measures that tell us how spread the values are in a distribution.

Because the standard deviation depends upon the mean, i.e., to calculate it we need to subtract each value or score from the mean, square the result, divide it by the total number of scores and finally take the square root for it, we have to conclude that with an inappropriate mean, the standard deviation is not a good measure for the dispersion of the data, in this case (a positively skewed distribution).

Since the median represents a central tendency measure in which 50% of the values for distribution falls below and above this value, no matter if the distribution is skewed, the median is the best measure to describe the center of the distribution in this case.

Likewise, the quartiles are not affected by skewness, since they represent values of the distribution for which there is a percentage of data below and above it. For example, the first quartile (which is also the 25th percentile) splits the lowest 25% of the data from the highest 75% of them, and the third quartile, the highest 25%, and the lowest 75%. In other words, those values do not change, no matter the extreme values or skewness.

For these reasons, we can say that the median and the interquartile range (IQR) describe the center and the spread for the distribution presented, and not the most usual measures such as the mean and standard deviation.