Ask question

Ask question

All categories

3 years ago

12

A road crew must repave a road that is 2/5 miles long. They can repave 1/30 miles each hour. How long will it take the crew to r

epave the road?

1 answer:

ladessa [460]3 years ago

8 0

2/5 = 12/30
1/30*12 = 12/30
It will take them 12 hours to repave the road.

You might be interested in

Triangles L M N and L K N are connected at side L N. A line is drawn from point M to point K and intersects side L N at point P.

lesya692 [45]

The true statement is Line MK is the perpendicular bisector of LN and ML is ≅ MN.

<h3>What is perpendicular?</h3>

Perpendicular lines are lines that intersect at a right (90 degrees) angle.

Given:

Δ LMN and Δ LKN are connected at side LN.

As per the information,

Line MK is the perpendicular bisector of LN. and ML ≅ MN.

Learn ore about this concept here:

brainly.com/question/25397944

#SPJ1

8 0

2 years ago

bekas [8.4K]

The percent off the store should display is 27.0%

The initial percent off given to Matt = 20%

The additional percent off given to Matt = 7%

The percent off the store should display is the total percent off given to their product. That is, the addition of the first and second percent off.

The total percent off the store gave to Matt is calculated as;

= 20% + 7%

= 27%

To the nearest tenth of a percent = 27.0%

Thus, the percent off the store should display is 27.0%

Learn more here: brainly.com/question/16956055

3 0

2 years ago

Write 5.306 in word form.

elena-14-01-66 [18.8K]

Five and three hundred and six thousandths.

3 0

4 years ago

Read 2 more answers

In parallelogram abcd, ab=14, bc=20, m(angle)b=54. Find to the nearest tenth the length of diagonal bd, and find measure angle d

muminat

It is is a parallelogram, hence we have to face sides equal in length and the opposite angles are also the same. From the given above we have:
ab=14 and its opposite side cd=14
bc=20 and its opposite side da=20

Solving for the diagonal measurement bd, we have consecutive angles are equal to 180°
∠A+∠B=180°
∠A=180°-54°
∠A=126° , ∠B=54° ,∠C=126° and ∠D=54°
bd²=ab²+da²-2(ab)(da)cos126°
bd²=14²+20²-2*14*20cos126°
bd=30.42 unit

Solving for the angle dbc, we have
cos dbc=bc²+bd²-cd²/a*bc*bd
cos dbc=20²+30.42²-14²/2*20*30.42
dbc=21.76°

3 0

3 years ago

I xyzdS<br> trong đó S là phần mặt<br> 2 2<br> z x y<br> nằm giữa hai mặt phẳng z =<br> 0 và z = 1

Anni [7]

Step-by-step explanation:

ewtjsgmsgmgdmgqrhwtjwth<u>w</u><u>t</u><u>j</u>

<u> $= . { {y1 {11.1 \times 3 { { {?}^{?} }^{?} }^{?} }^{?} }^{2} }^{2}$ </u>

<u>v</u><u>a</u><u>d</u><u>b</u><u>s</u><u>t</u><u>j</u><u>t</u><u>w</u><u>j</u><u>s</u><u>g</u><u>j</u><u>d</u><u>g</u><u>n</u><u>d</u><u>y</u><u>m</u><u>a</u><u>r</u><u>h</u><u>e</u><u>d</u><u>v</u><u>d</u><u>h</u><u>s</u><u>t</u><u>j</u><u>w</u><u>t</u><u>k</u><u>t</u><u>w</u><u>d</u><u>g</u><u>h</u><u>a</u><u>r</u><u>j</u><u>q</u><u>r</u><u>j</u><u>w</u><u>r</u><u>j</u><u>g</u><u>j</u><u>t</u><u>k</u><u>s</u><u>t</u><u>j</u><u>t</u><u>s</u><u>j</u><u>a</u><u>f</u><u>b</u><u>s</u><u>f</u><u>n</u><u>a</u><u>f</u><u>h</u><u>a</u><u>f</u><u>b</u><u>s</u><u>f</u><u>h</u><u>t</u><u>s</u><u>h</u><u>q</u><u>w</u><u>d</u><u>g</u><u>j</u><u>w</u><u>j</u><u>d</u><u>j</u><u>d</u><u>n</u><u>n</u><u>x</u><u>n</u><u>x</u><u>i</u><u>f</u><u>j</u><u>n</u><u>r</u><u>n</u><u>t</u><u>h</u><u>r</u><u>w</u><u>h</u><u>s</u><u>t</u>

<u> $22 {y)bvzv \cot( \beta log( \sec( log( \cot( \sec( \beta \alpha \pi \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( log(?) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) \times \frac{?}{?} }^{2}$ </u>

<u>hfzbcEdfgaywjshhsbxbxbxb</u><u>. </u><u> </u><u>s</u><u>e</u><u>z</u><u>n</u><u>n</u><u>x</u><u>n</u><u>d</u><u>n</u><u>d</u><u>n</u><u>n</u><u>d</u><u>n</u><u>x</u><u>n</u><u>b</u><u>x</u><u>h</u><u>x</u><u>u</u><u>d</u><u>u</u><u>d</u><u>h</u><u>b</u><u>d</u><u>x</u><u>h</u><u>h</u><u>b</u><u>x</u><u>h</u><u>j</u><u>x</u><u>j</u><u>d</u><u>b</u><u>n</u><u>z</u><u>j</u><u>s</u><u>n</u><u>s</u><u>n</u><u>n</u><u>z</u><u>n</u><u>z</u><u>i</u><u>d</u><u>n</u><u>x</u><u>n</u><u>s</u><u>b</u><u>n</u><u>z</u><u>j</u><u>x</u><u>l</u><u>d</u><u>k</u><u>d</u><u>j</u><u>d</u><u>n</u><u>b</u><u>x</u>

4 0

3 years ago